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sammy [17]
2 years ago
12

What is work - energy theorem ??​

Physics
2 answers:
velikii [3]2 years ago
7 0

Answer:

The work-energy theorem explains the idea that the net work - the total work done by all the forces combined - done on an object is equal to the change in the kinetic energy of the object

Explanation:

The work-energy theorem states that the work done by the net force acting on a body is equal to the change produced in the kinetic energy of the body. Let F. be the variable force. We have, W=xf∫xiF.

Elden [556K]2 years ago
3 0

The work-energy theorem explains the idea that the net work - the total work done by all the forces combined - done on an object is equal to the change in the kinetic energy of the object. After the net force is removed (no more work is being done) the object's total energy is altered as a result of the work that was done.

This idea is expressed in the following equation:

is the total work done

is the change in kinetic energy

is the final kinetic energy

is the initial kinetic energy

mark me as brainliest ❤️

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The energy of an electromagnetic wave changes proportionally to which
ozzi

Answer:

D. Frequency

Explanation:

The energy of an  electromagnetic wave is proportional to frequency, mathematically it is expressed as;

E ∝ f

E = hf

where;

h is Planck's constant = 6.626 x 10⁻³⁴ Js

The equation above can also be expanded to;

E = hf = h \frac{c}{\lambda}

where;

c is speed of light = 3 x 10⁸ m/s

λ is the wavelength of the electromagnetic wave

Since the speed of light is constant, we can conclude that the energy of the electromagnetic wave is directly proportional to its frequency and inversely proportional to its wavelength.

Therefore, the correct option for direct proportionality is FREQUENCY

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Answer:

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What information can scientists obtain from tree rings?

Answer's <u>I chose</u>:

<h3>how narrow the rings are</h3><h3>how the climate changed in the tree’s life</h3><h3>how wide the rings are</h3>

Please <u>correct</u> me if there are <em>more </em>or <em>less</em>

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