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2 years ago

What is work - energy theorem ??

Physics

2 answers:

velikii [3]2 years ago

7 0

Answer:

The work-energy theorem explains the idea that the net work - the total work done by all the forces combined - done on an object is equal to the change in the kinetic energy of the object

Explanation:

The work-energy theorem states that the work done by the net force acting on a body is equal to the change produced in the kinetic energy of the body. Let F. be the variable force. We have, W=xf∫xiF.

Elden [556K]2 years ago

3 0

The work-energy theorem explains the idea that the net work - the total work done by all the forces combined - done on an object is equal to the change in the kinetic energy of the object. After the net force is removed (no more work is being done) the object's total energy is altered as a result of the work that was done.

This idea is expressed in the following equation:

is the total work done

is the change in kinetic energy

is the final kinetic energy

is the initial kinetic energy

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3 years ago

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A certain car engine delivers enough force to create 630 N⋅m of torque when the engine is operating at 3200 revolutions per minu

jekas [21]

The appropriate expression for the calculation of power by relating the angular energy in a given time.

In other words the instantaneous power of an angular accelerating body is the torque times the angular velocity

$P=\tau\omega$

Where

$\tau =$ Torque

$\omega =$ Angular speed

Our values are given by

$\tau = 630Nm$

$\omega = 3200rev/min$

The angular velocity must be transformed into radians per second then

$\omega = 3200rev/min (\frac{2\pi rad}{60s})$

$\omega = 335.103rad/s$

Replacing,

$P=(630)(335.103)$

$P = 211.11*10^3W$

$P = 211.1kW$

The average power delivered by the engine at this rotation rate is 211.1kW

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3 years ago

which statement below is FALSE? A Gravity acts on any object with mass. B The closer objects are, the stronger the gravitational

GenaCL600 [577]

Answer:

Explanation:

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3 years ago

I have no idea of how to approach this problem

nataly862011 [7]

Answer:

p=1

Explanation:

Well me know that v=m/s

and that a=m/s^2

$(m/s)^{2} = (m/s^2)(x^p)\\\\(m^2/s^2)/(m/s^2)=x^p\\\\m^2s^2/ms^2=x^p\\\\(m^2/m)(s^2/s^2)=x^p\\\\m=x^p\\\\p=1$

Note: We don't take into account 2 because it's a scalar, it doesn't have units so it doesn't add anything to the equation.

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3 years ago

Is it possible for an object at rest to have forces acting upon it? Explain

daser333 [38]

Answer:

Yeah

Explanation:

I mean, how about gravity for example! When you draw a free-body diagram, you will almost always have to include gravity. How about normal force, or static friction? There are defintely forces at hand.

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3 years ago

What is work - energy theorem ??​

What is work - energy theorem ??