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3 years ago

Writeanyto increasemagnitude of current in dynamo

Physics

1 answer:

Svetach [21]3 years ago

4 0

Answer:

Explanation:

It can be increased by: increasing the rate of rotation. Increasing the strength of the magnetic field. Increasing the number of turns on the coil.

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What does resonance result in?

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“The vibrations of the aluminum force the air Column inside of the rod to vibrate at its natural frequency. The match between the vibrations of the air column and one of the natural frequencies of the singing rod causes resonance.”

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A window washer drops a brush from a scaffold on a tall office building. What is the speed of the falling brush after 3.28 s? (N

valina [46]

Answer:

The speed of washer will be 32.144 m/s

Explanation:

Given that

time t= 3.28 s

Acceleration due to gravity

$g=9.8\ \frac{m}{s^2}$

Here acceleration is constant so we cam apply the motion equation

we know that

v= u + at

At initial condition u =0 m/s

v= u + at

v= 0 + 9.8 x 3.28

v= 32.144 m/s

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A block of mass 2. 0 kg, starting from rest, is pushed with a constant force across a horizontal track. The position of the bloc

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The magnitude of the change in momentum of the block between zero and 4. 0 seconds is

dp=1.6m/s

<h3>What is the magnitude of the change in momentum of the block between zero and 4. 0 seconds?</h3>

Generally, the equation for the kinematics equation is mathematically given as

x=x+ut+0.5at^2

Therefore

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3 years ago

Assume the average value of the vertical component of Earth's magnetic field is 42 μT (downward) in some region that has an area

Oliga [24]

Answer:

The net magnetic flux through the rest of Earth's surface is $5.782\times10^{-2}\ T$

Explanation:

Given that,

Magnetic field = 42 μT

Area $A=3.71\times10^{5}\ km^2$

$A=3.71\times10^{11}\ m^2$

We need to calculate the flux per unit area

$flux\ per\ unit\ area=\dfrac{42\times10^{-6}}{3.71\times10^{11}}$

$flux\ per\ unit\ area=1.132\times10^{-16}\ T/m^2$

We need to calculate the total earth's surface area

$A'=4\pi r^2$

$A'=4\times\pi\times(6.3781\times10^{6})^2$

$A'=5.1120\times10^{14}\ m^2$

We need to calculate the rest of earth's area

$A''=A-A'$

Put the value into the formula

$A''=5.1120\times10^{14}-3.71\times10^{11}$

$A''=5.10829\times10^{14}\ m^2$

We need to calculate the net magnetic flux through the rest of Earth's surface

$B'=5.10829\times10^{14}\times1.132\times10^{-16}$

$B'=5.782\times10^{-2}\ T$

Hence, The net magnetic flux through the rest of Earth's surface is $5.782\times10^{-2}\ T$

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4 years ago

Explain why you can hear two people talking even after they walk around a corner.

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Writeanyto increasemagnitude of current in dynamo​

Writeanyto increasemagnitude of current in dynamo