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3 years ago

THE RIGHT ANSWER WILL RECIEVE A BRAINLEST AND POINTS AND THANXS!!!

1 answer:

3 0

1 - Chemistry is a branch of science focusing on elements, reactions, and chemicals.

2 - We study chemistry to learn more about these chemicals and elements and to discover new chemicals as well as to answer questions in life about reactions.

3 - Chemistry relates to our life in various ways, from the chemicals we inhale to the basic reactions in cooking and baking.

4 - The main branches of Chemistry are Physical, analytical, biochemistry, organic and inorganic chemistry.

Hope this helps!

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Which of the following changes depending on the strength of the gravity field it is in?

Lelechka [254]

Im pretty sure it weight because when we are on different plants with a different amount of gravitational pull our weight changes

hope this helps :)

4 0

3 years ago

Read 2 more answers

For hydrocyanic acid, HCN, Ka = 4.9 × 10-10. Calculate the pH of 0.20 M NaCN. What is the concentration of HCN in the solution?

gogolik [260]

By using the ICE table :

initial 0.2 M 0 0
change -X + X +X
Equ (0.2 -X) X X

when Ka = (X) (X) / (0.2-X)
so by substitution:

4.9x10^-10 = X^2 / (0.2-X) by solving this equation for X
∴X ≈ 10^-6
∴[HCN] = 10^-6

and PH = -㏒[H+]
= -㏒ 10^-6
= 6

3 0

3 years ago

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Which describes the earth as an open system with respect to energy?

Naddik [55]

Answer:

Explanation:

Any system within the Earth system is considered an open system. Because energy flows freely into and out of systems, all systems respond to inputs and, as a result, have outputs.

6 0

2 years ago

Given the following reaction: NH4SH (s) <--> NH3 (g) + H2S (g) If we start

almond37 [142]

Answer:

D. 0.3 M

Explanation:

NH4SH (s) <--> NH3 (g) + H2S (g)

Initial concentration 0.085mol/0.25L 0 0

Change in concentration -0.2M +0.2 M +0.2M

Equilibrium 0.035mol/0.25 L=0.14M 0.2M 0.2M

concentration

Change in concentration (NH4SH) = (0.085-0.035)mol/0.25L =0.2M

K = [NH3]*[H2S]/[NH4SH] = 0.2M*0.2M/0.14M ≈ 0.29 M ≈ 0.3M

4 0

3 years ago

Identify the products formed in this Brønsted-Lowry reaction.<br><br> HPO2−4+NO−2↽−−⇀acid+base

klemol [59]

Answer: The products formed in this Bronsted-Lowry reaction are $HNO_{2}$ and $PO^{2-}_{4}$ .

Explanation:

According to Bronsted-Lowry, acids are the species which donate hydrogen ions to another specie in a chemical reaction.

Bases are the species which accept a hydrogen ion upon chemical reaction.

For example, $HPO^{2-}_{4} + NO^{-}_{2} \rightleftharpoons HNO_{2} + PO^{2-}_{4}$

Here, the products formed in this Bronsted-Lowry reaction are $HNO_{2}$ and $PO^{2-}_{4}$ .

Thus, we can conclude that the products formed in this Bronsted-Lowry reaction are $HNO_{2}$ and $PO^{2-}_{4}$ .

5 0

3 years ago