Answer:
Explanation:
Given that,
Stiffness K=460N/m
Extension e=0.37m
Two balls attached to a string
First ball has mass and velocity
M1 =8kg and V1~ =4i +11j +0k
For the second ball
M2 =4kg and V2~ =-3i+10j +0k
a. Momentum of system?
Momentum is given as
P = m1•V1~ +m2•V2~
P= 8(4i +11j +0k) +4(-3i+10j +0k)
P=32i + 88j + 0k -12i +40j + 0k
P= 20i + 128j + 0k kgm/s
2. Magnitude of each velocity is given as
V1²=Vx² +Vy² + Vz²
V1² =4²+11²+0²
V1² =137
V1 =√137
V1=11.705m/s
Also V2
V2²= Vx² +Vy² +Vz²
V2²=(-3)²+(10)² +0²
V2²=109
V2 = √109
V2 =10.44m/s
Ktot= k(trans) +k(rel)
d. K(trans) =½m1•V1²
K(trans) =½×8×11.705²
K(trans) = 548.03J
e. K(rel) =½m2•V2²
K(rel) =½ ×4×10.44²
K(rel) = 217.99J
c. Then, K(tot)=K(trans)+k(rel)
K(tot) =548.03+217.99
K(tot) = 766.02J
The SI unit of force is Newton.
Newton is denoted by N.
Force can be defined as the pull or push which change or try to change the state of a body from motion to rest or rest to motion in a straight line.
It is called a warm-up.
