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3 years ago

you are asked to draw a triangle with side length of 10in,7in and 2in how many triangles like this can you draw

Mathematics

1 answer:

Aleks [24]3 years ago

5 0

None because two sides of the triangle added together have to be greater than the other side

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Please help whats the answer

klasskru [66]

The Answer is -12x+6

7 0

3 years ago

Sasha needs to score at least 360 points

IgorC [24]

93.
EXPLANATION:
Add all the numbers together
- that from 360
93

5 0

3 years ago

Find the perimeter and area of the composite shape...

tatiyna

Answer:

P = 30

A = 22

Step-by-step explanation:

Find perimeter first

P = 5 + 5 + 2 + 2 + 2 + 2 + 2 + 2 + 4 + 4

P = 10 + 12 + 8

P = 30

Now area

A = 2(5 * 2) + (2 * 1)

A = 2(10) + (2)

A = 20 + 2

A = 22

6 0

3 years ago

Read 2 more answers

Find the area of the helicoid (or spiral ramp) with vector equation r(u, v) = ucos(v) i + usin(v) j + v k, 0 ≤ u ≤ 1, 0 ≤ v ≤ 9π

Natasha2012 [34]

Let $H$ denote the helicoid parameterized by

$\mathbb r(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+v\,\mathbf k$

for $0\le u\le1$ and $0\le v\le9\pi$ . The surface area is given by the surface integral,

$\displaystyle\iint_H\mathrm dS=\iint_H\|\mathbf r_u\times\mathbf r_v\|\,\mathrm du\,\mathrm dv$

We have

$\mathbf r_u=\dfrac{\partial\mathbf r(u,v)}{\partial u}=\cos v\,\mathbf i+\sin v\,\mathbf j$
$\mathbf r_v=\dfrac{\partial\mathbf r(u,v)}{\partial v}=-u\sin v\,\mathbf i+u\cos v\,\mathbf j+\mathbf k$
$\implies\mathbf r_u\times\mathbf r_v=\sin v\,\mathbf i-\cos v\,\mathbf j+u\,\mathbf k$
$\implies\|\mathbf r_u\times\mathbf r_v\|=\sqrt{1+u^2}$

So the area of $H$ is

$\displaystyle\iint_H\mathrm dS=\int_{v=0}^{v=9\pi}\int_{u=0}^{u=1}\sqrt{1+u^2}\,\mathrm du\,\mathrm dv$
$=\dfrac{9(\sqrt2+\sinh^{-1}(1))\pi}2$

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3 years ago

What we get when we multiply the number by a integer

ycow [4]

The answer is gonna be Negative

4 0

3 years ago