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Answer:
The unit cell edge length for the alloy is 0.405 nm
Explanation:
Given;
concentration of Ag, = 78 wt%
concentration of Pd, = 22 wt%
density of Ag = 10.49 g/cm³
density of Pd = 12.02 g/cm³
atomic weight of Ag, = 107.87 g/mol
atomic weight of iron, = 106.4 g/mol
Step 1: determine the average density of the alloy
Step 2: determine the average atomic weight of the alloy
Step 3: determine unit cell volume
for a FCC crystal structure, there are 4 atoms per unit cell; n = 4
Step 4: determine the unit cell edge length
Vc = a³
= 0.405 nm
Therefore, the unit cell edge length for the alloy is 0.405 nm