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Step2247 [10]
2 years ago
5

What is true of all atoms?

Chemistry
2 answers:
Klio2033 [76]2 years ago
7 0

Answer:

Atoms are the building blocks of matter. They are the smallest particles of an element that still have the element's properties. All atoms are very small, but atoms of different elements vary in size. Three main types of particles that make up all atoms are protons, neutrons, and electrons.

Explanation:

mestny [16]2 years ago
5 0

Answer:

Atoms are the basic building blocks for life

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On the first day of school, a class of th-grade students are given tour identical cubes of hard clay. The cubes are placed in fo
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sample 4

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To decrease the rate of reaction you would ... *
STALIN [3.7K]
Answer: it’s number 2 add a catalyst

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4 0
3 years ago
Read 2 more answers
Consider the reaction below for which K = 78.2 atm-1. A(g) + B(g) ↔ C(g) Assume that 0.386 mol C(g) is placed in the cylinder re
borishaifa [10]

Answer:

1.65 L

Explanation:

The equation for the reaction is given as:

                        A            +            B           ⇄        C

where;

numbers of moles = 0.386 mol C  (g)

Volume =  7.29 L

Molar concentration of C = \frac{0.386}{7.29}

= 0.053 M

                        A            +            B           ⇄        C

Initial               0                           0                      0.530    

Change          +x                          +x                       - x

Equilibrium      x                           x                      (0.0530 - x)

K = \frac{[C]}{[A][B]}

where

K is given as ; 78.2 atm-1.

So, we have:

78.2=\frac{[0.0530-x]}{[x][x]}

78.2= \frac{(0.0530-x)}{(x^2)}

78.2x^2= 0.0530-x

78.2x^2+x-0.0530=0  

Using quadratic formula;

\frac{-b+/-\sqrt{b^2-4ac} }{2a}

where; a = 78.2 ; b = 1 ; c= - 0.0530

= \frac{-b+\sqrt{b^2-4ac} }{2a}   or \frac{-b-\sqrt{b^2-4ac} }{2a}

= \frac{-(1)+\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}  or \frac{-(1)-\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}

= 0.0204  or -0.0332

Going by the positive value; we have:

x = 0.0204

[A] = 0.0204

[B] = 0.0204

[C] = 0.0530 - x

     = 0.0530 - 0.0204

     = 0.0326

Total number of moles at equilibrium = 0.0204 +  0.0204 + 0.0326

= 0.0734

Finally, we can calculate the volume of the cylinder at equilibrium using the ideal gas; PV =nRT

if we make V the subject of the formula; we have:

V = \frac{nRT}{P}

where;

P (pressure) = 1 atm

n (number of moles) = 0.0734 mole

R (rate constant) = 0.0821 L-atm/mol-K

T = 273.15 K  (fixed constant temperature )

V (volume) = ???

V=\frac{(0.0734*0.0821*273.15)}{(1.00)}

V = 1.64604

V ≅ 1.65 L

3 0
3 years ago
When dilute HCL is added to zinc pieces taken in a test tube​
Romashka-Z-Leto [24]

Answer:

zince chloride will be formed and hydrogen gas will be librated.

Explanation:

When dilute HCl is added to zinc pieces, a rection will takes place as follows :

Zn+HCl\rightarrow ZnCl_2+H_2

It means that zinc chloride will form when zinc reacts with dilute HCL. Also hydrogen gas will produced.

As zinc is more reactive than hydrogen, it displaces hydrogen from its solution and forms zinc chloride. The form product is white in color and H₂ is an odorless gas.

Hence, zince chloride will be formed and hydrogen gas will be librated.

6 0
3 years ago
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