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3 years ago

What passes through the Haversian canal

1 answer:

4 0

A Haversian canal is referred to as any minute tube, which forms a network in a bone and also contains blood vessels. Blood vessels, nerve fibers and lymphatics may pass through the Haversian canal. Haversian canals are found surrounding blood vessels and nerve cells all over the bones and interacts with bone cells from end to end networks known as canaliculi.

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Whose main job is to break down sugar to release energy that a plant cell can use?

Tasya [4]

Answer:

The Mitochondria

Explanation:

Mitochondria are membrane-bound cell organelles that generate most of the energy required to power the cell's organic chemistry reactions. Energy created by the mitochondria is kept in a tiny molecule known as adenosine triphosphate (ATP).

3 0

3 years ago

. the density (d) of a substance is an intensive property that is defined as the ratio of its mass (m) to its volume (v). densit

ale4655 [162]

Density is intensive because it is the ratio of two extensive properties that is mass to volume.

<h3>What is Density ?</h3>

Density is defined as mass per unit volume. S.I unit if density is kg/m³.

It is expressed as

Density = $\frac{\text{Mass}}{\text{Volume}}$ or $d = \frac{m}{V}$

<h3>What is Intensive Property ? </h3>

Intensive property is the property which does not depend on the size of the system. Intensive property can be easily identified. Intensive property is the independent property. The size does not change in this.

Example of intensive property are Density, Freezing point, melting point, colour, Lustre, etc.

<h3>What is Extensive property ?</h3>

Extensive property is the property which depend on the substance. Extensive property cannot be easily identified.

Example of extensive property length, weight, volume, mass etc.

Thus from the above conclusion we can say that Density is intensive because it is the ratio of two extensive properties that is mass to volume.

Learn more about Density here: brainly.com/question/1354972

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Disclaimer: The given question is incomplete on the portal. Here is the complete question.

Question: The density (d) of a substance is an intensive property that is defined as the ratio of its mass (m) to its volume (v)

density = $\frac{\text{Mass}}{\text{Volume}}$ or $d = \frac{m}{V}$

Considering that mass and volume are both extensive properties, explain why their ratio, density is intensive.

5 0

2 years ago

How many grams of CaCl, are needed to make a 15% by mass solution with 520g of water?

allsm [11]

Answer:

many

Explanation:

many many many many

5 0

3 years ago

A 25.0 ml solution of .0600 M EDTA was added to a 57.0 ml sample containing an unknown concentration of V3+. All V3+ present for

Rom4ik [11]

Explanation:

Let us assume that the ratio for the given reaction is 1:1.

Therefore, we will calculate the moles of $Ga^{3+}$ as follows.

Moles of $Ga^{3+}$ solution = molarity × volume (L)

= 0.0440 M × 0.014 L

= 0.000616 moles

Moles of excess EDTA = 0.000616 moles

Also, the initial moles of EDTA will be calculated as follows.

Total initial moles of EDTA = 0.0600 M × 0.025 L

= 0.0015

Therefore, moles of EDTA reacted with $V^{3+}$ will be as follows.

= 0.0015 - 0.000616

= 0.00088 moles

Since, we have supposed a 1 : 1 ratio between $V^{3+}$ and EDTA .

So, moles of $V^{3+}$ = 0.00088 moles

Now, we will calculate the molarity of $V^{3+}$ as follows.

Molarity of $V^{3+}$ solution = $\frac{\text{moles}}{\text{volume (L)}}$

= $\frac{0.00088 moles}{0.057 L}$

= 0.015 M

Thus, we can conclude that the original concentration of the $V^{3+}$ solution is 0.015 M.

4 0

3 years ago

Convert 1.65 × 1024 atoms of carbon to moles of carbon.

gogolik [260]

The number of moles in a substance indicates the amount of the substance that contains the same number of particles as 12 g of the Carbon-12 isotope [or equivalent to 6.02 × 10²³] (which is used as a standard in the world of moles).

Now,

if 6.02 × 10²³ atoms are found in 1 mole of C
then let 1.65 × 10²⁴ atoms are found in x

⇒ x = (1.65 × 10²⁴) ÷ (6.02 × 10²³)

= 2.7409 mol
<span>

A sample of 1.65 × 10</span>²⁴ atoms of Carbon (C) would contain ~ 2.74 mol

6 0

3 years ago