Answer: The molar volume of any gas at standard pressure and standard temperature is 22.4 liters per mole.
Explanation:The ideal gas law is PV=nRT
P is pressure and if we consider standard pressure, then we have 1.00 atm.
V is volume and that is what we are trying to solve.
n is the number of moles, which is 1.00 moles since we are trying to determine the volume of a gas in one mole.
R is the ideal gas constant which equals
0.0821 (Liters x atmospheres)/(mole x kelvin)
T is the standard temperature which is 273 kelvin.
Rearrange the equation to solve for volume.
V = nRT/P
V = (1.00 mol)(0.0821 L atm/mol K)(273 K)/ 1.00 atm
V = 22.4 L
Answer:
DONT PRESS THAT THAT IS HACK AND VIRUS
Explanation:
The complete reaction of the problem, for better illustration, is
FeO(s) + CO(g) <--> Fe(s) + CO2(g)
The double-tailed arrow signifies that the reaction is in a dynamic chemical equilibrium. When the system is in equilibrium, the forward and the backward reaction rates have an equal ratio of Kp = 0.403 at 1000°C. The formula for Kp is
Kp = [partial pressure of products]/[partial pressure of reactants]
So, first, let's find the partial pressure of the compounds in the reaction.
FeO(s) + CO(g) <--> Fe(s) + CO2(g)
Initial x 1.58 0 0
Change -1.58 -1.58 +1.58 +1.58
------------------------------------------------------------------
Equilbrium x-1.58 0 1.58 1.58
Kp = [(1.58)(1.58)]/[(x-1.58)] = 0.403
x = 7.77 atm (this is the amount of excess FeO)
Therefore, the partial pressure of CO2 at equilibrium is 1.58 atm. There is no more CO because it has been consumed due to excess FeO.
Answer:
The correct answer is 27.764 grams.
Explanation:
A standard scientific unit for determining the large quantities of very small entities like molecules, atoms, or other specific particles is termed as a mole. The molecular weight of lithium is 6.941 grams per mole. Thus, one mole of lithium has 6.941 grams.
If, 1 mole of Li has 6.941 grams, then 4 moles of Lithium will have,
= Molecular mass of lithium/1 mole * 4 mole
= 6.941 gram per mole/1 mole * 4 moles.
= 27.764 grams