Answer: B -Network solids
Ionic solids are held by positive and negative charged ions bonded by electrostatic forces. The electrostatic force is much stronger than dipole–dipole interactions, London dispersion forces, hydrogen bonding.
Molecular solids are held by dipole–dipole interactions, London dispersion forces, or hydrogen bonds. Benzene is an example of this. These inter-molecular force are much weaker than electrostatic force.
The metallic bonds are much weaker than electrostatic force. Similarly, in non-metallic solids the atoms are held by covalent bonds. These covalent bonds are weaker than the electrostatic force.
Thus we can conclude that electrostatic force is the strongest when compared to dipole–dipole interactions, London dispersion forces, hydrogen bonding,covalent and metallic bonds. Thus ionic solids will have the highest melting point as more energy is required to break the ionic bonds as this is the strongest bond compared to the other bonds.
H20 can be a molecule or a compound because it is made up of Hydrogen(H)
and oxygen (O)
Answer: none of the above
Explanation:
It should be 2,1,1,2 to give a balanced chemical reaction
Answer:
Augite or other dark-colored Pyroxene minerals
Explanation:
Basalt is given a dark color because it has a high amount of Augite and other dark-colored Pyroxene minerals.
Answer:
Option-C (27.36% Na, 1.20% H, 14.30% C, and 57.14% O)
Explanation:
<em>Percent Composition</em> is defined as the <u><em>%age by mass of each element present in a compound</em></u>. Therefore, it is a relative amount of each element present in a compound.
Calculating Percent Composition of NaHCO₃:
1: Calculating Molar Masses of all elements present in NaHCO₃:
a) Na = 22.99 g/mol
b) H = 1.01 g/mol
c) C = 12.01 g/mol
d) O₃ = 16.0 × 3 = 48 g/mol
2: Calculating Molecular Mass of NaHCO₃:
Na = 22.99 g/mol
H = 1.01 g/mol
C = 12.01 g/mol
O₃ = 48 g/mol
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Total 84.01 g/mol
3: Divide each element's molar mass by molar mass of NaHCO₃ and multiply it by 100:
For Na:
= 22.99 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100
= 27.36 %
For H:
= 1.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100
= 1.20 %
For C:
= 12.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100
= 14.29 % ≈ 14.30 %
For O:
= 48.0 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100
= 57.13 % ≈ 57.14 %