We know that molarity = mol/L, so:
1.5 M = x mol/0.345 L
1.5 M * 0.345 L = x mol => 0.5175 mol
0.5175 mol/0.250 L = 2.07 M
Your new molarity of the solution will be 2.07 M.
Ca(OH)₂ ==> Ca²⁺ + 2 OH<span>-
Ca(OH)</span>₂ is <span>strong Bases</span><span>
</span>Therefore, the [OH-] equals 5 x 10⁻⁴ M. For every Ca(OH)₂ you produce 2 OH⁻<span>.
</span>
pOH = - log[ OH⁻]
pOH = - log [ <span>5 x 10⁻⁴ ]
pOH = 3.30
pH + pOH = 14
pH + 3.30 = 14
pH = 14 - 3.30
pH = 10.7
hope this helps!</span>
Freezer and refrigerator--> Too cold for most bacteria to grow (reproduce). Oven --> too hot for bacteria to survive
Could you attach a picture because I can tell you didn't post the entire question.
Answer:
I got the answers but it won't let me post it correctly on here....
Explanation:
9.) 10-2.76 =0.0174 [H30+]= 1.74*10-3 M
10.)10-3.65=0.00224 [H3O+] =2.24*10-2 M
11.)10-3.65=0.00224 [OH-]= 2.224*10-4M
12.)10-6.87=0.00000135 [OH-]= 1.35*10-7M
