Ksp = [Ba⁺²][SO₄⁻²]
[Ba⁺²] = [SO₄⁻²] for barium sulfate
Thus,
Ksp = (1 x 10⁻⁵)²
Ksp = 1 x 10⁻¹⁰
Answer: 4.7m/s²
Explanation:
According to newton's first law,
Force = mass × acceleration
Since we are given more the one force, we will take the resultant of the two vectors.
Mass = 2.0kg
F1+F2 = (3i-8j)+(5i+3j)
Adding component wise, we have;
F1+F2 = 3i+5i-8j+3j
F1+F2 = 8i-5j
Resultant of the sum of the forces will be;
R² = (8i)²+(-5j)²
Since i.i = j.j = 1
R² = 8²+5²
R² = 64+25
R² = 89
R = √89
R = 9.4N
Our resultant force = 9.4N
Substituting in the formula
F = ma
9.4 = 2a
a = 9.4/2
a = 4.7m/s²
Therefore, magnitude of the acceleration of the particle is 4.7m/s²
Answer: actually to solve this u must know what 3.2m/s2 is..do u know it ??...wel let me tell...3.2m/s2 means that in every second the speed of the body increases by 3.2m/s..so if it acts for 6.8 seconds..increase in speed will be 3.2*6.8 however note that this is the increase in speed.. have to change this in km/hr & add this to the initial speed(27km/hr) to get the answer....hope this has cleared ur doubts....
Explanation:
