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3 years ago

The desinty of a metal is 8.9g/cm3.what does it mean? what is the importance of this value?

Physics

2 answers:

prohojiy [21]3 years ago

6 0

Answer:

it means that the mass of 1 cm^3 of the metal is 8.9 grams.

The density is used to approximate how heavy and object is going to be. The mass of an object with known density and volume can be calculated using;

Mass = density × volume

Density is used to determine whether an object would float or sink in water of other substances.

Density is also considered in the selection of materials for construction, fabrications and manufacturing of products

Explanation:

Density is the measure of compactness of a substance. It is simply the mass of a unit volume of a substance.

Density = mass/volume

If the desinty of a metal is 8.9g/cm^3, it means that the mass of 1 cm^3 of the metal is 8.9 grams.

That means that the mass of a unit volume (1cm^3) of the metal is 8.9 g.

The density is used to approximate how heavy and object is going to be. The mass of an object with known density and volume can be calculated using;

Mass = density × volume

Density is used to determine whether an object would float or sink in water of other substances.

Density is also considered in the selection of materials for construction, fabrications and manufacturing of products

Komok [63]3 years ago

5 0

Answer:

It means that in every cubic centimeter volume of the metal, there is 8.9 grams mass of the metal.

Explanation:

It means that the degree of compaction of the atoms of the metal is 8.9 g/cm3.

It also means that in every cubic centimeter volume of the metal, there is 8.9 grams mass of the metal.

This information (density) will help us to understand how dense the the metal is, whether it will float or sink when immersed in a certain fluid.

Example, this metal will sink when it is immersed in water, because density of water is 1g/cm3, which is less than the density of the metal.

Also, this metal will float when immersed in a fluid like heavy crude oil, whose density is great than 8.9g/cm3.

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3 years ago

If you can swim in still water at 0.5m/s, the shortest time it would take you to swim from bank to bank across a 20m wide river,

expeople1 [14]

Answer:

t=40s,

Explanation:

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3 years ago

Read 2 more answers

A body oscillates with simple harmonic motion along the x-axis. Its displacement varies with time according to the equation x =

abruzzese [7]

I'll tell you how I look at this, although I may be missing something important.

Position = x(t) = 0.5 sin(pt + p/3)

Speed = position' = x'(t) = 0.5 p cos(pt + p/3)

Acceleration = speed' = position ' ' = x ' '(t) = -0.5 p² sin(pt + p/3)

At (t = 1.0),

x ' '(t) = -0.5 p² sin( 4/3 p )

In order to evaluate this, don't I still have to know what 'p' is ? ?

I don't think it can be evaluated with the information given in the question.

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3 years ago

Establishing a potential difference The deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. A 10

11111nata11111 [884]

Answer:

$1.62\times 10^{-8}\ \text{s}$

Explanation:

$\epsilon_0$ = Vacuum permittivity = $8.854\times 10^{-12}\ \text{F/m}$

$A$ = Area = $10\times 2\times 10^{-4}\ \text{m}^2$

$d$ = Distance between plates = 1 mm

$V_c$ = Changed voltage = 60 V

$V$ = Initial voltage = 100 V

$R$ = Resistance = $1000\ \Omega$

Capacitance is given by

$C=\dfrac{\epsilon_0A}{d}\\\Rightarrow C=\dfrac{8.854\times 10^{-12}\times 10\times 2\times 10^{-4}}{1\times 10^{-3}}\\\Rightarrow C=1.7708\times 10^{-11}\ \text{F}$

We have the relation

$V_c=V(1-e^{-\dfrac{t}{CR}})\\\Rightarrow e^{-\dfrac{t}{CR}}=1-\dfrac{V_c}{V}\\\Rightarrow -\dfrac{t}{CR}=\ln (1-\dfrac{V_c}{V})\\\Rightarrow t=-CR\ln (1-\dfrac{V_c}{V})\\\Rightarrow t=-1.7708\times 10^{-11}\times 1000\ln(1-\dfrac{60}{100})\\\Rightarrow t=1.62\times 10^{-8}\ \text{s}$

The time taken for the potential difference to reach the required level is $1.62\times 10^{-8}\ \text{s}$ .

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