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stira [4]
3 years ago
15

The eficiency of a simple machine can never be 100% why?​

Physics
1 answer:
Kitty [74]3 years ago
6 0

Answer:

Systems always tend toward a state of decreasing order unless more energy is provided into the system to counteract this tendency.

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Will give Brianliest answer. help.
dimaraw [331]

Answer:6.2

Explanation:

3 0
2 years ago
Sonar is used to locate objects underwater by measuring the time it takes an ultrasound sound pulse to reflect back to the recei
Romashka-Z-Leto [24]

Answer:

The floor of the ocean is 6120 m deep.

Explanation:

In order to find the depth of the ocean we need to use the speed of the ultrasonic sound 1530 m/s and the time it takes for the echo to comeback. Since the wave is transmitted by the vessel goes to the bottom of the ocean and comeback, it travels the distance between the vessel and the floor two times, so we can divide the time by two. We then have:

D = V*t/2 = 1530*8/2 = 1530*4 = 6120 m

8 0
3 years ago
How does a sound wave transfer energy to your ears ?
horrorfan [7]

Answer:

A. Particles in air move in circles as the wave moves forward.

B. Particles in air move forward but not backward as the wave moves

forward.

C. Particles in air move up and down as the wave moves forward.

✔ D. Particles in air move forward and backward as the wave moves

forward.

Explanation:

The waves transfer energy from the source of the sound, e.g. a drum, to its surroundings. Your ear detects sound waves when vibrating air particles cause your ear drum to vibrate. The bigger the vibrations the louder the sound.

7 0
3 years ago
Read 2 more answers
PLEASE HELP THIS IS FOR SCIENCE!!!!
Oksana_A [137]

Answer:

xd vchrfdjtrytft5fttydi765ri756ir56ri75ri75f7tf6tykf5rf65ty gfgcjg

Explanation:

fgjcfrcfjcv mghkckgktygftgvkytfyfvky

8 0
2 years ago
Consider a satellite in a circular orbit around the Earth. If it were at an altitude equal to twice the radius of the Earth, 2RE
Elenna [48]

Answer:

v=\sqrt{\frac{gR_E}{2}}

Explanation:

Satellites experiment a force given by Newton's Gravitation Law:

F=\frac{GMm}{r^2}

where M is Earth's mass, m the satellite's mass, r the distance between their gravitational centers and G the gravitational constant.

We also know from Newton's 2nd Law that <em>F=ma, </em>so putting both together we will have:

ma=\frac{GMm}{r^2}

a=\frac{GM}{r^2}

If we are on the surface of the Earth, the acceleration would be g and r=R_E (Earth's radius):

g=\frac{GM}{R_E^2}

Which we will write as:

gR_E^2=GM

If we are on orbit the acceleration is centripetal (a=\frac{v^2}{r}), so we have:

\frac{v^2}{r}=a=\frac{GM}{r^2}=\frac{gR_E^2}{r^2}

v^2=\frac{gR_E^2}{r}

v=\sqrt{\frac{gR_E^2}{r}}

And if this orbit has a radius r=2R_E we have:

v=\sqrt{\frac{gR_E^2}{2R_E}}=\sqrt{\frac{gR_E}{2}}

3 0
3 years ago
Read 2 more answers
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