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2 years ago

If you were to model water particles before and after the deposition how would they compare

Chemistry

2 answers:

ruslelena [56]2 years ago

5 0

Answer:

it would be dense before

Explanation:before would be much denser

MatroZZZ [7]2 years ago

3 0

Answer:

dense before

Explanation:

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“Enter the conjugate acids of no2- and no3-“

Rainbow [258]

Answer:

nitrit,nitrat

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2 years ago

What happens in the redox reaction below? Select all that apply.

vladimir2022 [97]

Answer:

B- Sodium loses an electron.

D- Fluorine gains an electron.

Sodium is oxidized.

Explanation:

The reaction equation is given as:

Na + F → NaF

In this reaction, Na is the reducing agent. It loses an electron and then becomes oxidized. By so doing, Na becomes isoelectronic with Neon.

Fluorine gains the electron and then becomes reduced. This makes fluorine also isoelectronic with Neon.

This separation of charges on the two species leads to an electrostatic attraction which forms the ionic bonds.

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2 years ago

How many atoms are in 85.1 grams of neon

strojnjashka [21]

Convert the mass to moles .

85.1 g ÷ 20.18 g/mol = 4.21704658

convert the moles to molecules

4.2170 mol × 6.022^23 molecules/mol = 2.539^24

7 0

3 years ago

An unknown compound with a molar mass of 223.94 g/mol consists of 32.18% c, 4.50% h, and 63.32% cl. find the molecular formula f

Dima020 [189]

The actual number of atoms of each element present in the molecule of the compound is represented by the formula known as molecular formula.

Molar mass of the unknown compound = 223.94 g/mol (given)

Mass of each element present in the unknown compound is determined as:

Mass of carbon, $C$ :

$\frac{32.18}{100}\times 223.94 = 72.06 g$

Mass of hydrogen, $H$ :

$\frac{4.5}{100}\times 223.94 = 10.08 g$

Mass of chlorine, $Cl$ :

$\frac{63.32}{100}\times 223.94 = 141.79 g$

Now, the number of each element in the unknown compound is determined by the formula:

$number of moles = \frac{given mass}{molar mass}$

Number of moles of $C$ :

$number of moles = \frac{72.06}{12} = 6.005 mole\simeq 6 mole$

Number of moles of $H$ :

$number of moles = \frac{10.08}{1} = 10.08 mole\simeq 10 mole$

Number of moles of $Cl$

$number of moles = \frac{141.79}{35.5} = 3.99 mole\simeq 4 mole$

Dividing each mole with the smallest number of mole, to determine the empirical formula:

$C_{\frac{6}{4}}H_{\frac{10}{4}}Cl_{\frac{10}{4}}$

$C_{1.5}H_{2.5}Cl_{1}$

Multiplying with 2 to convert the numbers in formula into a whole number:

So, the empirical formula is $C_{3}H_{5}Cl_{2}$ .

Empirical mass = $12\times 3+1\times 5+2\times 35.5 = 112 g/mol$

In order to determine the molecular formula:

n = $\frac{molar mass}{empirical mass}$

n = $\frac{223.94}{112} = 1.99 \simeq 2$

So, the molecular formula is:

$2\times C_{3}H_{5}Cl_{2} = C_{6}H_{10}Cl_{4}$

6 0

3 years ago

When an acidic molecule is added to water it will ____________ the pH of the solution because it increases the number of free __

Dahasolnce [82]

Lower the pH because increased number of free hydrogen ions

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2 years ago