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Rina8888 [55]
3 years ago
15

If you were to model water particles before and after the deposition how would they compare

Chemistry
2 answers:
ruslelena [56]3 years ago
5 0

Answer:

it would be dense before

Explanation:before would be much denser

MatroZZZ [7]3 years ago
3 0

Answer:

dense before

Explanation:

PLEASE MARK BRAINLIEST IF THIS HELPED

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He predicted an element with an atomic weight between 65 (zinc) and 75 (arsenic) with a valence similar to aluminum that he name
skad [1K]

Answer:

Scandium

Explanation:

Mendeleev played an important role in the development of the modern periodic table. His periodic table was filled with gaps. He said that these gaps were elements that were yet to be discovered. He rightly predicted many elements which have now been discovered and fitted in their proper places in the periodic table.

He used the prefix ''eka'' to refer to elements whose properties were alike but were yet to be discovered at that time.

The compound named ekaboron which he predicted to have an atomic weight between 65 (zinc) and 75 (arsenic) with a valence similar to aluminum was later discovered in 1879 and properly named scandium.

3 0
3 years ago
Please show all of your work! :)
Paladinen [302]

Answer:

A

Explanation:

To answer this, we need to use Gay-Lussac's law, which states that:

\frac{P_1}{T_1}= \frac{P_2}{T_2} , where P is pressure and T is temperature

The initial pressure we're given is 4.5 atm (so P1 = 4.5) and the temperature is 45.0°C; however, we need to change Celsius to Kelvins, so add 273 to 45.0: 45.0 + 273 = 318 K (so T1 = 318).

The final pressure is what we want to find, but we do know the final temperature is 3.1°C. Converting this to Kelvins, we get: 3.1 + 273 = 276.1 K, which means T2 = 276.1.

Plug these values in:

\frac{P_1}{T_1}= \frac{P_2}{T_2}

\frac{4.5}{318}= \frac{P_2}{276.1}

Multiply both sides by 276.1:

P_2 ≈ 3.9 atm

The answer is thus A.

3 0
3 years ago
WILL GIVE BRAINLIEST
dedylja [7]

Answer:

In order to be able to solve this problem, you will need to know the value of water's specific heat, which is listed as

c=4.18Jg∘C

Now, let's assume that you don't know the equation that allows you to plug in your values and find how much heat would be needed to heat that much water by that many degrees Celsius.

Take a look at the specific heat of water. As you know, a substance's specific heat tells you how much heat is needed in order to increase the temperature of 1 g of that substance by 1∘C.

In water's case, you need to provide 4.18 J of heat per gram of water to increase its temperature by 1∘C.

What if you wanted to increase the temperature of 1 g of water by 2∘C ?

This will account for increasing the temperature of the first gram of the sample by n∘C, of the the second gramby n∘C, of the third gram by n∘C, and so on until you reach m grams of water.

And there you have it. The equation that describes all this will thus be

q=m⋅c⋅ΔT , where

q - heat absorbed

m - the mass of the sample

c - the specific heat of the substance

ΔT - the change in temperature, defined as final temperature minus initial temperature

In your case, you will have

q=100.0g⋅4.18Jg∘C⋅(50.0−25.0)∘C

q=10,450 J

4 0
3 years ago
Select all that are true
kipiarov [429]
I think it’s B not quite sure ! Sorry
8 0
3 years ago
Essential amino acids cannot be made
sattari [20]

Answer:

True

Explanation:

There are 9 essential amino acids which cannot be made by the body and have to be obtained from food.

They are histidine, isoleucine, leucine, lysine, methionine, phenylalanine, threonine, tryptophan, and valine

4 0
3 years ago
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