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2 years ago

The half-life of carbon-14 is approximately 5700 years. An archaeologist unearths a piece of wood that is determined to

Chemistry

1 answer:

masha68 [24]2 years ago

7 0

The age of the ancient piece of wood that she located given the data is 1482 years

How to determine the number of half-lives

Original amount (N₀) = 100%

Amount remaining (N) = 83%

Number of half-lives (n) =?

2ⁿ = N₀ / N

2ⁿ = 100 / 83

2ⁿ = 1.2

Take the Log of both side

Log 2ⁿ = Log 1.2

nLog 2 = Log 1.2

Divide both side by Log 2

n = Log 1.2 / Log 2

n = 0.26

How to determine the age

Number of half-lives (n) = 0.26

Half-life (t½) = 5700 years

Time (t) =?

t = n × t½

t = 0.26 × 5700

t = 1482 years

Learn more about half life:

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Answer:

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3 years ago

179.1 g of water is in a Styrofoam calorimeter of negligible heat capacity. The initial T of the water is 16.1oC. After 306.9 g

taurus [48]

Answer:

the specific heat of the unknown compound is $c_u=0.412J/g \cdot C$

Explanation:

Generally the change in temperature of water is evaluated as

$\Delta T = T_2 -T_1$

Substituting 16.1°C for $T_1$ and 27.4°C for $T_2$

$\Delta T = 27.4 - 16.1$

$=11.3^oC$

Generally the change in temperature of unknown compound is evaluated as

$\Delta T_u = T_3 -T_2$

Substituting 27.4°C for $T_2$ and 94.3°C for $T_3$

$\Delta T = 94.3 - 27.4$

$=66.9^oC$

Since there is an increase in temperature then heat is gained by water and this can be evaluated as

$H_w = mc_w \Delta T$

Substituting 179.1 g for m , 4.18 J/g.C for $c_w$ (specific heat of water)

$H_w = 4.18 * 179.1 * 11.3$

$= 8459.6J$

Since there is a decrease in temperature then heat is lost by unknown compound and this can be evaluated as

$H_u = m_uc_u \Delta T_u$

By conservation of energy law

Heat lost = Heat gained

Substituting 306.9 g for $m_u$ , 8459.6J for $H_u$

$8459.6 = 306.9 * c_u * 66.9$

Therefore $c_u = \frac{8459.6}{308.9 *66.9}$

$=0.412J/g \cdot C$

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As the question tells you, you need to use the formula

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3 years ago

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