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s344n2d4d5 [400]
3 years ago
12

Please follow I will follow you​

Physics
2 answers:
svet-max [94.6K]3 years ago
7 0
Huh wdym, follow what,,,
klio [65]3 years ago
5 0

Answer:

aight

Explanation:

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The pressure inside a blimp is 506 Pa, if the area is 3,000cm2 then what is the force? ​
Zarrin [17]

Answer:

<h2>151.8 N</h2>

Explanation:

The force acting on the blimp can be found by using the formula

<h3>f = p × a</h3>

p is the pressure

a is the area

3000 cm² = 0.3 m²

From the question we have

f = 506 × 0.3

We have the final answer as

<h3>151.8 N</h3>

Hope this helps you

6 0
3 years ago
The 8 kg block is then released and accelerates to the right, toward the 2 kg block. The surface is rough and the coefficient of
natita [175]

Answer:

3.258 m/s

Explanation:

k = Spring constant = 263 N/m (Assumed, as it is not given)

x = Displacement of spring = 0.7 m (Assumed, as it is not given)

\mu = Coefficient of friction = 0.4

Energy stored in spring is given by

U=\dfrac{1}{2}kx^2\\\Rightarrow U=\dfrac{1}{2}\times 263\times 0.7^2\\\Rightarrow U=64.435\ J

As the energy in the system is conserved we have

\dfrac{1}{2}mv^2=U-\mu mgx\\\Rightarrow v=\sqrt{2\dfrac{U-\mu mgx}{m}}\\\Rightarrow v=\sqrt{2\dfrac{64.435-0.4\times 8\times 9.81\times 0.7}{8}}\\\Rightarrow v=3.258\ m/s

The speed of the 8 kg block just before collision is 3.258 m/s

7 0
3 years ago
What is the velocity of a wave with a wavelength of 3.7 m and a frequency of 22.5 Hz?
ExtremeBDS [4]

Answer: 343 m/s. The sound wave has a frequency of. 436 Hz. What is the period of the wave? T = = 436 Hz. = 2.29x10-3 s. C. What is the wave's wavelength? To halve

Explanation:

8 0
2 years ago
A train at a constant 60.0 km/h moves east for 40.0 min, then in a direction 50.0 degrees east of due north for 20.0 min, and th
son4ous [18]

Answer:

Part a)

v = 7.57 km/h

Part b)

\theta = 67.5 degreeNorth of East

Explanation:

Speed of train towards East = 60 km/h

displacement towards East is given as

d_1 = 40 km

now it turns towards 50 degree East of North

so its distance is given as

d_2 = 20 km(sin50 \hat i + cos50\hat j)

d_2 = 15.3 \hat i + 12.8 \hat j

then finally it moves towards west for 50 min

d_3 = -50 \hat i

Now the total displacement of the train is given as

d = d_1 + d_2 + d_3

d = (40 + 15.3 - 50)\hat i + 12.8 \hat j

d = 5.3\hat i + 12.8 \hat j

now total time duration of the motion is given as

T = 40 min + 20 min + 50 min

T = 1.83 h

now average velocity is given as

v_{avg} = \frac{5.3\hat i + 12.8\hat j}{1.83}

v_{avg} = 2.89\hat i + 6.99\hat j

Part a)

magnitude of the average velocity is given as

v = \sqrt{v_x^2 + v_y^2}

v = \sqrt{2.89^2 + 6.99^2}

v = 7.57 km/h

Part b)

Direction of the velocity is given as

tan\theta = \frac{v_y}{v_x}

tan\theta = \frac{6.99}{2.89}

\theta = 67.5 degreeNorth of East

6 0
3 years ago
Three-Dimensional Thinking
gavmur [86]

Answer:

A.

Explanation: both triple by 3

4 0
2 years ago
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