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2 years ago

Please follow I will follow you

Physics

2 answers:

svet-max [94.6K]2 years ago

7 0

Huh wdym, follow what,,,

klio [65]2 years ago

5 0

Answer:

aight

Explanation:

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The two forces acting on a skydiver are __________ and air _____________.

Stolb23 [73]

Answer:

Gravity and

Air resistance

Explanation:

The two forces acting on a skydiver are gravitational force and air resistance.

Gravitational force is a force that tends to pull all massive bodies towards the center of the earth. It works on all bodies that has mass. The larger or bigger the mass, the more the pull of gravity on the body.

Air resistance is the drag of air on a body as it passes to it. It is resisting force.

When a sky diver jumps out of a plane, he/she encounters both gravity and air resistance.
It soon balances both force and attain terminal velocity.
Air resistance is a frictional force that opposes motion.
This frictional force pushes in the opposite direction of motion
Motion direction is downward due to the celerity caused by gravity.

3 0

3 years ago

Read 2 more answers

On a certain planet, which is perfectly spherically symmetric, the free-fall acceleration has magnitude g = go at the north pole

ohaa [14]

The reason why there is a difference between free-fall acceleration is a centrifugal force.
I attached a diagram that shows how this force aligns with the force of gravity.
From the diagram we can see that:
$F=F_g-F_{cf}=mg'-mw^2r'cos(\alpha)\\ ma=mg'-mw^2r'cos(\alpha)\\ a=g'-w^2rcos^2(\alpha)\\$
Where g' is the free-fall acceleration when there is no centrifugal force, r is the radius of the planet, and w is angular frequency of planet's rotation. $\alpha$ is the latitude.
We can calculate g' and wr^2 from the given conditions in the problem.
$g(90)=g_0;\ g_0= g'-w^2rcos^2(90)\\
g_0=g'\\
g(0)=ag_0;\ ag_0=g_0-w^2rcos^2(0)\\
ag_0=g_0-w^2r\\
w^2r=g_0(a-1)
$
Our final equation is:
$g=g_0-g_0(a-1)cos^2(\alpha)$
Colatitude is:
$\alpha_c=90^\circ-\alpha$
The answer is:
$g=g_0-g_0(a-1)cos^2(90-9)=g_0-g_0(a-1)sin^2(9)$

5 0

3 years ago

With a velocity of 15 m/s, how long would it take the dog to run 100 meters?

Zinaida [17]

Answer

6.66 seconds imma seem like an idiot if something like this is werong

Explanation:

dogg is speed

100/15

3 0

3 years ago

Read 2 more answers

a boy throw a ball upward from the top of a cliff 73m high.Calculate the time in which ball will fall on the ground and the velo

LekaFEV [45]

The ball rises for v/g seconds; which equals 14.7/9.8=1.5 seconds . After this time, it’s height will be:

h(t)=g/2(1.5)²+14.7(1.5)

=-4.9 x 2.25 + 22.05

=11.025m

The ball then falls for 49+11.025=60.025m, which takes:

g/2t²=60.025

t²=12.25

t=3.5 secs

Total time: 1.5+3.5=5 seconds

3 0

3 years ago

Pls help<br> What graph indicates no reference to direction of motion, and explain why.

Komok [63]

Answer:

graph A

Explanation:

the slope of the distance-time graph is speed, speed is a scalar (with magnitudes but no direction)

but the slope for the velocity time graph is acceleration, acceleration is vector quantity ( has magnitude and direction)

4 0

3 years ago

Please follow I will follow you​

Please follow I will follow you