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kotykmax [81]
3 years ago
10

A 6,600 kg train car moving at +2.0 m/s bumps into and locks together with one of mass 5,400 kg moving at -3.0 m/s.

Physics
1 answer:
Katarina [22]3 years ago
5 0
Option B would be right one
according to momentum conservation
6600*2 = 13200kgm/s
5400*3 = 16200kgm/s
16200-13200 = 3000
now 6600-5400 = 1200 kg
thus 3000/1200 = 2.5 v
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Answer:

The decrease in decibels is 0.1 dB.

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Let the intensity of one chorus is Io.

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The intensity of 1000 vocalist is 1000 Io.

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let the intensity of 999 vocalist is dB'.

dB' = 10log\frac{999Io}{Io}=29.9..... (2)

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c. 43 m/s

Explanation:

Given the following data;

Displacement, S = 90 meters

Time, t = 5.55 seconds

To find the initial velocity;

We would use the second equation of motion given by the formula;

S = ut + \frac {1}{2}at^{2}

Where;

  • S represents the displacement or height measured in meters.
  • u represents the initial velocity measured in meters per seconds.
  • t represents the time measured in seconds.
  • a represents acceleration measured in meters per seconds square.

We know that acceleration due to gravity is -9.8m/s² because the direction is downward.

Substituting into the equation, we have;

90 = u*5.55  + \frac {1}{2}*(-9.8)*5.55^{2}

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