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kotykmax [81]
3 years ago
10

A 6,600 kg train car moving at +2.0 m/s bumps into and locks together with one of mass 5,400 kg moving at -3.0 m/s.

Physics
1 answer:
Katarina [22]3 years ago
5 0
Option B would be right one
according to momentum conservation
6600*2 = 13200kgm/s
5400*3 = 16200kgm/s
16200-13200 = 3000
now 6600-5400 = 1200 kg
thus 3000/1200 = 2.5 v
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Answer:

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<em></em>

Explanation:

The equation for drag force is given as

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where F_{D} IS the drag force on the object

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u = relative velocity of the object through the fluid

p = density of the fluid

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Note that C_{D} is a dimensionless coefficient related to the object's geometry and taking into account both skin friction and form drag. The most interesting things is that it is dependent on the linear dimension, which means that it will vary directly with the change in diameter of the fluid

The above equation can also be broken down as

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which also clarifies that the drag force is approximately proportional to the abject's area.

<em>In this case, the object with the twice the area of the other object, will have the larger drag coefficient.</em>

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3 years ago
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Answer:

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Explanation:

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