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3 years ago

In a parallel circuit the current A stays in one path B splits and goes through two components C makes one circle

Physics

1 answer:

ArbitrLikvidat [17]3 years ago

8 0

Answer:

B splits and goes through two components

Explanation:

- A series circuit is a circuit in which the components are all connected along the same branch: as a result, the current flowing through the components is the same, while the sum of the potential differences across each component is equal to the emf of the battery

- A parallel circuit is a circuit consisting of separate branches, so that each branch has a potential difference equal to the emf of the battery. As a result, in such a circuit the current in the circuit splits and goes through the different branches/components.

So, the correct answer is

B splits and goes through two components

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it would not be safe to connect the electric cooker hob to the mains electricity supply by plugging it into a standard power soc

zvonat [6]

Answer:

Switches in mains circuits should always be included in the live wire so that when the switch is open no electrical energy can reach an appliance. If the switch is included in the neutral wire, electrical energy can still enter an appliance, and could possibly cause an electric shock (Figure 7.10).

Explanation:

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4 years ago

When is thermal equilibrium achieved between two identical objects?

Sindrei [870]

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3 0

3 years ago

How much current is drawn by a television with a resistance of 30 ω that is connected across a potential difference of 120v?

melomori [17]

By using the Ohms law, we can calculate the current.

Ohms law,

$\frac{V}{I} = R$

Here, V is potential difference, and R is the resistance.

Given, $V=120 V$ and $R = 30 ohm$ .

Therefore, putting the given values in above relation , we get

$\frac{120V}{I} = 30 ohm$

or $I=\frac{120}{30} = 4 A$

Thus, the current is drawn by a television 4 Ampere

8 0

4 years ago

A test charge of +4 µC is placed halfway between a charge of +6 µC and another of +2 µC separated by 20 cm. (a) What is the magn

S_A_V [24]

Answer:

(a) Magnitude: 14.4 N

(b) Away from the +6 µC charge

Explanation:

As the test charge has the same sign, the force that the other charges exert on it will be a repulsive force. The magnitude of each of the forces will be:

$F_e = K\frac{qq_{test}}{r^2}$

K is the Coulomb constant equal to 9*10^9 N*m^2/C^2, q and qtest is the charge of the particles, and r is the distance between the particles.

Let's say that a force that goes toward the +6 µC charge is positive, then:

$F_e_1 = K\frac{q_1q_{test}}{r^2}=-9*10^9 \frac{Nm^2}{C^2} \frac{6*10^{-6}C*4*10^{-6}C}{(0.1m)^2} =-21.6 N$

$F_e_2 = K\frac{q_2q_{test}}{r^2}=9*10^9 \frac{Nm^2}{C^2} \frac{2*10^{-6}C*4*10^{-6}C}{(0.1m)^2} =7.2 N$

The magnitude will be:

$F_e = -21.6 + 7.2 = -14.4 N$ , away from the +6 µC charge

3 0

4 years ago

Katie and Mark sit next to one another in class. She has a mass of 40 kg and his mass is 65 kg.

OlgaM077 [116]

A :-) for this question , we should apply
F = GMm by d^2
( For making the calculation easy , first remove the decimals )
Given : G = 6.7 x 10^-11 Nm^2 / kg^2
= 67 x 10^-12 Nm^2 / Kg^2
M = 65 kg
m = 40 kg
d = 0.5 m
Solution -
F = GMm by d^2
F = 67 x 10^-12 x 65 x 40 by 0.5 x 0.5
F = 4355 x 40 x 10^-12 by 0.25
F = 174200 x 10^-12 by 0.25
F = 696800 x 10^-12

.:. The Gravitational force between mark and Katie is 696800 x 10^-12

6 0

3 years ago