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Juli2301 [7.4K]
3 years ago
6

Evaluate 12P3 and 10C3

Mathematics
1 answer:
jeka57 [31]3 years ago
3 0
12P3=\dfrac{12!}{9!}=10\cdot11\cdot12=1320\\\\
10C3=\dfrac{10!}{3!7!}=\dfrac{8\cdot9\cdot10}{2\cdot3}=120

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Answer:

1. C. Yes, because a sum of cubes can be factored

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