3 years ago

Evaluate 12P3 and 10C3

Mathematics

1 answer:

jeka57 [31]3 years ago

3 0

$12P3=\dfrac{12!}{9!}=10\cdot11\cdot12=1320\\\\
10C3=\dfrac{10!}{3!7!}=\dfrac{8\cdot9\cdot10}{2\cdot3}=120
$

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