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Akimi4 [234]
3 years ago
9

NaOH + HCl -> Fe + HCl ->

Chemistry
1 answer:
vfiekz [6]3 years ago
5 0

Answer:

This is an oxidation-reduction (redox) reaction:

2 HI + 2 e- → 2 H0 (reduction)

Fe0 - 2 e- → FeII (oxidation)

HCl is an oxidizing agent, Fe is a reducing agent.

Reactants:

Fe

Names: Iron source: wikidata, accessed: 2019-09-07, Fe source: wikidata, accessed: 2019-09-07, Element 26 source: wikidata, accessed: 2019-09-07... show more

HCl – Chlorane source: wikipedia, accessed: 2019-09-27, Hydrogen chloride source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02

Other names: Hydrochloric acid sourc2 2019-09-27source: NIOSH NPG, accessed: 2019-09-02, M source: wikipedia, accessed: 2019-09-27, Uriatic acid source: wikipedia, accessed: 2019-09-27... show more

Appearance: Colorless, transparent liquid, fumes in air if concentrated source: wikipedia, accessed: 2019-09-27; Colorless gas source: wikipedia, accessed: 2019-09-27; Colourless compressed liquefied gas with pungent odour source: ICSC, accessed: 2019-09-04; Colorless to slightly yellow gas with a pungent, irritating odor. [Note: Shipped as a liquefied compressed gas.] source: NIOSH NPG, accessed: 2019-09-02

Products:

FeCl2 – Iron(II) chloride source: : 2019-09-27source: ICSC, accessed: 2019-09-04, Iron dichloride source: wikipedia, accessed: 2019-09-27source: ICSC, accessed: 2019-09-04

Other names: Ferrous chloride source 2019-09-27source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04, Rokühnite source: wikipedia, accessed: 2019-09-27, [FeCl3] source: wikidata, accessed: 2019-09-02, FeCl3 source: wikidata, accessed: 2019-09-02

Appearance: Tan solid (anhydrous) | Pale green solid (di-tetrahydrate) source: wikipedia, accessed: 2019-09-27; White-to-light-green hygroscopic crystals source: ICSC, accessed: 2019-09-04

H2

Names: Dihydrogen source 2019-09-07, Hydrogen source: ICSC, accessed: 2019-09-04source: wikidata, accessed: 2019-09-07, H2 source: wikidata, accessed: 2019-09-07... show more

Appearance: Odourless colourless compressed gas source: ICSC, accessed: 2019-09-04

Hope this helps

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A 25.0 ml sample of 0.150 m hydrazoic acid is titrated with a 0.150 m naoh solution. what is the ph after 15.0 ml of the sodium
babunello [35]
First, we need to calculate moles of hydrazoic acid NH3:

moles NH3 = molarity * volume 

                    = 0.15 m * 0.025 L

                   =  0.00375 moles

moles NaOH = molarity * volume 

                       = 0.15 m * 0.015 L

                       = 0.00225 moles 

after that we shoul get the total volume = 0.025L + 0.015L

                                                                   = 0.04 L

So we can get the concentration of NH3 & NaOH by:

∴[NH3] = moles NH3 / total volume 

           = 0.00375 moles / 0.04 L

           = 0.09375 M

∴[NaOH] = moles NaOH / total volume 

                = 0.00225 moles / 0.04 L

                = 0.05625 M

then, when we have the value of Ka of NH3 so we can get the Pka value from:

Pka = -㏒Ka 

       = - ㏒ 1.9 x10^-5

      = 4.7 

finally, by using H-H equation we can get PH:

PH = Pka + ㏒[salt/ basic]

PH = 4.7 +㏒[0.05625/0.09375]

∴ PH = 4.48 


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3 years ago
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Feliz [49]

Answer:

D

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In a Helium (He) atom, the atomic structure of the atom has 2 protons, 2 electrons and 2 neutrons. For an element X to be a Helium (He) atom, it must possess 2 protons. The number of neutrons present will determine its stability either if its probably radioactive or a natural occurring inert gas.

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We have H-2. The symbol "H" is used to denote the element hydrogen in the periodic table and hydrogen has only 1 protons and 1 neutron making its mass number 2.

Option 2,

He -2 : here in this option, we have a helium atom, but with mass number of 2 only. Judging from the formula of mass number = protons + neutrons, we already have proton as 2, hence the number of neutrons there is zero (0)

Option 3,

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Option 4,

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<h3>Further explanation </h3>

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\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

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