I think its Na3(PO4)+Cu(SO4) --> Na2(SO4) + Cu3(2PO4). Hope am right
Answer:
Hydrogen, 0,2 mol
Explanation:
= 22, 4 l/mol
V () = 6,72 = 6,72 l
V () = 6,72 = 6,72 l
The formula is:
n =
n () = 6,72l /22,4 l/mol = 0,3 mol
n () = 6,72l /22,4 l/mol = 0,3 mol (the same)
But from the equation we get a proportion that 1 mol () - 3 mol ()
(we have more hydrogen than is need for the reaction)
So there is excess of
We only need = 0,1 mol ()
0,3 mol (hydrogen quantity we have) - 0,1 mol (hydrogen quantity we need for the reaction) = 0,2 mol (excess)
make me the brainliest
Answer:
0.102 M
Explanation:
Given data
- Mass of sucrose (solute): 35.0 g
- Volume of solution: 1.000 L
Step 1: Calculate the moles of solute
The molar mass of sucrose is 342.3 g/mol. The moles corresponding to 35.0 g of sucrose are:
Step 2: Calculate the molarity of sucrose in the solution
The molarity is equal to the moles of solute divided by the liters of solution.
3 sf
<span>(Rules:
> Non-zero digits are always significant.
123 - 3sf
> Any zeros between two significant digits are significant.
102 - 3 sf
<span>> A final zero or trailing zeros in the decimal portion ONLY are significant.
4500 - 2 sf
0.04 - 1 sf
0.0013 - 2 sf )
</span></span>