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soldier1979 [14.2K]
3 years ago
8

What is the percentages of Carbon, Hydrogen and oxygen in C6H12O6

Chemistry
1 answer:
lara31 [8.8K]3 years ago
6 0
First calculate the Ar of the compound.. ( Ar of C6H12O6 is 180)
Then divide the At of the required element by 180 and multiply by 100...

 so, for carbon 12 * 6 = 72 (THERE ARE 6 CARBON ATOM)
  
                            (72/180) * 100 =40%
    ITS THE SAME FOR THE OTHER 2 ELEMENT
            
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What mass of solid that has a molar mass of 46.0 g/mol should be added to 150.0 g of benzene to raise the boiling point of benze
enyata [817]

Answer : 17.12 g

Explanation:\Delta T =k_b\times m

\Delta T = elevation in boiling point

k_b = boiling point elevation constant

m= molality

molality=\frac{mass of solute}{molecular mass of solute\times weight of the solvent in kg}

given \Delta T=6.28^{\circ}C

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Weight of the solvent = 150.0 g = 0.15 kg

Putting in the values

molality=\frac{x}{46gmol^{-1}\times0.15kg}

6.28 =2.53^{\circ}Ckgmol^{-1}\frac{x}{46gmol^{-1}\times 0.15kg}

x = 17.12 g



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Answer:

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