What is the percentages of Carbon, Hydrogen and oxygen in C6H12O6

1 answer:

6 0

First calculate the Ar of the compound.. ( Ar of C6H12O6 is 180)
Then divide the At of the required element by 180 and multiply by 100...

so, for carbon 12 * 6 = 72 (THERE ARE 6 CARBON ATOM)

                          (72/180) * 100 =40%
    ITS THE SAME FOR THE OTHER 2 ELEMENT

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