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3 years ago

HELP ME PLEASE

Physics

2 answers:

lawyer [7]3 years ago

8 0

Yeah the answer is d

Stels [109]3 years ago

7 0

The answer is B. the germinal stage

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Calcular la rapidez promedio

Vlada [557]

Answer:

v_average = 15 m / s

Explanation:

The average speed can be found in two ways,

* taking the distance traveled and divide it by the time spent

* taking the velocities in each time interval and then finding the weighted average by the time fraction

v_average = 1 / t_total ∑ $v_{i} t_{i}$ vi ti

Let's apply this last equation

Total time is

t = t₁ + t₂

t = 10 + 10 = 20 min

v_average = 10/20 10 + 10/20 20

v_average = 10/2 + 20/2

v_average = 15 m / s

7 0

3 years ago

A boy standing on the bridge kicks a stone into the water below. He kicks the stone with a horizontal velocity of 8.06 m/s. It l

Ronch [10]

Time taken to reach water :

$t = \dfrac{D}{v}\\\\t=\dfrac{6.78}{8.06}\ s\\\\t=0.84\ s$

Now, initial vertical speed , u = 0 m/s.

By equation of motion :

$h = ut +\dfrac{at^2}{2}$

Here, a = g = acceleration due to gravity = 9.8 m/s².

So,

$h = 0(t) +\dfrac{9.8\times 0.84^2}{2}\\\\h=3.46\ m$

Therefore, the height of the bridge is 3.46 m.

Hence, this is the required solution.

6 0

3 years ago

What happens to the mass and volume if density increases

nikitadnepr [17]

They all stay the same regardless

7 0

3 years ago

Liquids take the shape of the bottom of their container, while gases take the shape of their entire container. The shape solids

motikmotik

Answer:

...

Explanation:

sigh its not that hard

Any liquid takes form of the shape of the container it goes into.

Gasses take the form of the whole thing because it spreads throughout it.

Solids are already a shape so it cant take the shape of the container if it already has one. yk

4 0

3 years ago

A 18.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.9-T magnetic field. The loop is rotated so that its p

Alchen [17]

Answer:

0.3405V

Explanation:

#Given a magnetic field of $1.9T$ , diameter= 18.5cm(r=9.25cm or 0.0925m), we find the magnetic flux of the loop as:

$\phi=B.(\pi r^2)cos 0\textdegree\\=1.9\pi\times 0.0925^2 \times cos 0\textdegree\\=5.107\times10^-^2 \ Tm^2$

we can now calculate the induced emf, $\frac{\phi}{\bigtriangleup t}$ :

$\frac{\phi}{\bigtriangleup t}=\frac{5.107\times 10^-^2}{0.15}\\=3.405\times 10^-^1V$

Hence, the induced emf of the loop is 0.3405V

8 0

3 years ago

﻿HELP ME P﻿LEASE﻿﻿

HELP ME PLEASE