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horrorfan [7]
3 years ago
9

A baseball travelling horizontally at 41 m/s [S] is hit by a baseball bat, causing its velocity to become 47 m/s [N]. The ball i

s in contact with the bat for 1.9 ms, and undergoes constant acceleration during this interval. What is that acceleration?
Physics
1 answer:
dmitriy555 [2]3 years ago
8 0

Answer:

46.3\times 10^3 m/s^2

Explanation:

We are given that

Initial velocity of baseball=u=-41m/s

Because final and initial velocity are in opposite direction

Final velocity of baseball=v=47m/s

Time=t=1.9 ms=1.9\times 10^{-3} s

1 ms=10^{-3} s

We have to find the acceleration .

We know that

Acceleration=a=\frac{v-u}{t}

Using the formula

Acceleration=a=\frac{47+41}{1.9\times 10^{-3}}m/s^2

Acceleration=46.3\times 10^3 m/s^2

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Rina8888 [55]

Can you add more information to this question?

3 0
3 years ago
1 Point
irakobra [83]

Answer:

SECOND LAW OF NEWTON

Explanation:

When the rocket fires the engines the gases leave at high speed and collide with the space station, transferring an impulse given by the expression

                I = F t = Δp

As we can see this expression is a form of Newton's second law

           F = m a

           a = dv / dt

           F = m dv / dt

           F dt = m dv

           p = mv

           F dt = dp

Therefore the station moves through the SECOND LAW OF NEWTON

7 0
3 years ago
A jet is travelling at a speed of 1200 km/h and drops cargo from a height of 2.5 km above the ground Calculate the time it takes
OLEGan [10]

a) Time of flight: 22.6 s

To calculate the time it takes for the cargo to reach the ground, we just consider the vertical motion of the cargo.

The vertical position at time t is given by

y(t) = h +u_y t - \frac{1}{2}gt^2

where

h = 2.5 km = 2500 m is the initial height

u_y = 0 is the initial vertical velocity of the cargo

g = 9.8 m/s^2 is the acceleration of gravity

The cargo reaches the ground when

y(t) = 0

So substituting it into the equation and solving for t, we find the time of flight of the cargo:

0 = h - \frac{1}{2}gt^2\\t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(2500)}{9.8}}=22.6 s

b) 7.5 km

The range travelled by the cargo can be calculated by considering its horizontal motion only. In fact, the horizontal motion is a uniform motion, with constant velocity equal to the initial velocity of the jet:

v_x = 1200 km/h \cdot \frac{1000 m/km}{3600 s/h}=333.3 m/s

So the horizontal distance travelled is

d=v_x t

And if we substitute the time of flight,

t = 22.6 s

We find the range of the cargo:

d=(333.3)(22.6)=7533 m = 7.5 km

7 0
3 years ago
A4) A straight wire that is 0.60 m long is carrying a current of 2.0 A. It is placed in a uniform magnetic field of strength 0.3
Klio2033 [76]

Answer:

\theta=30^{\circ}

Explanation:

It is given that,

Length of the wire, L = 0.6 m

Current flowing inside the wire, I = 2 A

Uniform magnetic field, B = 0.3 T

Force experienced by the wire in the magnetic field, F = 0.18 N

To find,

The angle made by the wire with the magnetic field.

Solve,

We know that the magnetic force acting on the wire inside the magnetic field is given by :

F=ILB\ sin\theta

sin\theta=\dfrac{F}{ILB}

sin\theta=\dfrac{0.18}{2\times 0.6\times 0.3}

\theta=30^{\circ}

Therefore, the wire makes an angle of 30 degrees with respect to magnetic field.

5 0
3 years ago
Acceleration is often measured in what unit? A. newtons B. kilograms C. meters per second D. meters per second squared
spayn [35]

D. meters per second squared

3 0
4 years ago
Read 2 more answers
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