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horrorfan [7]
3 years ago
9

A baseball travelling horizontally at 41 m/s [S] is hit by a baseball bat, causing its velocity to become 47 m/s [N]. The ball i

s in contact with the bat for 1.9 ms, and undergoes constant acceleration during this interval. What is that acceleration?
Physics
1 answer:
dmitriy555 [2]3 years ago
8 0

Answer:

46.3\times 10^3 m/s^2

Explanation:

We are given that

Initial velocity of baseball=u=-41m/s

Because final and initial velocity are in opposite direction

Final velocity of baseball=v=47m/s

Time=t=1.9 ms=1.9\times 10^{-3} s

1 ms=10^{-3} s

We have to find the acceleration .

We know that

Acceleration=a=\frac{v-u}{t}

Using the formula

Acceleration=a=\frac{47+41}{1.9\times 10^{-3}}m/s^2

Acceleration=46.3\times 10^3 m/s^2

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