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3 years ago

For the triangles to be congruent by HL, what must be the value of x?

Mathematics

1 answer:

lilavasa [31]3 years ago

6 0

Answer:

x = 8

Step-by-step explanation:

For the triangles to be congruent, then the legs

ED = AB, that is

4x + 2 = 34 ( subtract 2 from both sides )

4x = 32 ( divide both sides by 4 )

x = 8

You might be interested in

(−t 4 −5t 3 −10t 2 )+(9t 3 +3t 2 −1)

klemol [59]

Answer:

$\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1$

Step-by-step explanation:

Given the expression

$\left(-t^4\:-5t^3\:-10t^2\:\right)+\left(9t^3\:+3t^2\:-1\right)$

Remove parentheses: (a)=a

$=-t^4-5t^3-10t^2+9t^3+3t^2-1$

Group like terms

$=-t^4-5t^3+9t^3-10t^2+3t^2-1$

Add similar elements

$=-t^4-5t^3+9t^3-7t^2-1$ ∵ $-10t^2+3t^2=-7t^2$

Add similar elements

$=-t^4+4t^3-7t^2-1$ ∵ $-5t^3+9t^3=4t^3$

Thus, the equivalent expression in simplified form:

$\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1$

4 0

3 years ago

There are 10 true-false questions and 20 multiple choice questions from which to choose a five-question quiz how many ways can t

beks73 [17]

Answer:

In 68229 ways can the quiz be selected such that there is atleast three multiple choice questions

Step-by-step explanation:

Given:

Number of True or false questions= 10

Number of multiple choice questions= 20

To Find:

How many ways can 5 questions can be selected if there must be at least three multiple choice questions =?

Solution:

Combination

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order.

The question States there sholud be ATLEAST 3 multiple choice question,

So, we may have

(3 Multiple choice question and 2 true or false question) or

(4 Multiple choice question and 1 true or false question) or

(5 Multiple choice question and 0 true or false question)

Required Number of ways = (20C3 X10C2) +(20C4 X10C1) + (20C5 X10C0)

Required Number of ways $=(\frac{20!}{20!(20-3)!}\times\frac{10!}{10!(10-2)!})+(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-1)!}) +(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-0)!})$

Required Number of ways = ( 1140 x 42) + (4845 x 10) +(15504 x 1)

Required Number of ways = 47880+48450+15504

Required Number of ways = 68229

3 0

2 years ago

Solve for y in the following equation. x+2y=z

Galina-37 [17]

Answer:

The Answer:

Step-by-step explanation:

x+2y=z

minus x both sides

2y=z-x

divide by 2 both sides

The Answer:

$y = \frac{z - x}{2}$

6 0

3 years ago

Up arrow, right arrow, down arrow, left arrow, up arrow, right arrow, down arrow, left arrow, what’s the conjunction

AlladinOne [14]

Step-by-step explanation:

↑

→

↓

←

↑

→

↓

←

conjunction are the words that join 2 sentences

8 0

2 years ago

Which could the confederate flag? hi guys

JulijaS [17]

Answer:

Step-by-step explanation:

but that was no a question but thanks

6 0

2 years ago