Ax - c = 2x + 5
ax - c + c = 2x + 5 + c
ax = 2x + 5 + c
ax - 2x = 2x - 2x + 5 + c
ax - 2x = c + 5
X(a - 2) = c + 5
X(a - 2)/(a - 2) = c+5/(a-2)
X = c+5/a-2
I believe this would be the solution.
Cosine(angle) = adjacent leg/ hypotenuse
Cosine( angle ) = 18/20
Angle = arccos(18/20)
Angle = 26 degrees
308cm 2
V =14 V-6=8 - =22
K+K=14
22 x 14 =308
Answer:
The perimeter of triangle is 30ft.
Step-by-step explanation:
First you have to find the value of a using Pythogoras Theorem, a² + b² = c² where a and b is the sides and c is the hypotenuse :
Let b = 12,
Let c = 13,
Next you have to find the perimeter of triangle by adding all the sides together :
Answer:
Determine the next step for solving the quadratic equation by completing the square.
0 = –2x2 + 2x + 3
–3 = –2x2 + 2x
–3 = –2(x2 – x)
–3 + = –2(x2 – x + )
StartFraction negative 7 Over 2 EndFraction = –2(x – StartFraction 1 Over 2 EndFraction)2
StartFraction 7 Over 4 EndFraction = (x – StartFraction 1 Over 2 EndFraction)2
The two solutions are Plus or minus StartFraction StartRoot 7 EndRoot Over 2 EndFraction
-7/2 = -2(x - ½)²
Step-by-step explanation:
0 = –2x^2 + 2x + 3
Subtract 3 from each side
-3 = –2x^2 + 2x
Factor out the -2
-3 =- 2(x^2 -x)
Take the coefficient of x and divide by 2 and square it
-1 /2 = -1/2 ^2 = 1/4
Add it to each side Remember the -2 on the outside so we need to multiply it by -2
-2 *1/4 = -1/2
-3 -1/2= -2(x^2 -x +1/4)
-7/2 = -2(x^2 -x +1/4)
-7/2 = -2(x-1/2)^2
7/2 = -2(x - ½)²
