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-Dominant- [34]
4 years ago
6

Imagine the earth's hydrosphere began to dry up and disappear. all of the following would be affected except

Chemistry
2 answers:
RoseWind [281]4 years ago
6 0
Answer most suited would be A
katen-ka-za [31]4 years ago
3 0

A is right. I just took the test on plato.

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You happen to be visiting Northem California and you are driving by Suisun Bay, a notorious graveyard for old ships You notice t
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The rusting of the metal is a chemical change.

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3 years ago
What is the percent by mass of oxygen in carbon dioxide (CO2)?
krok68 [10]

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I think that it will be

Explanation:

72.71%

8 0
3 years ago
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Check all of the boxes that are true about the proton:
vovikov84 [41]

Answer:

it is outside the nucleus  F

it has a positive charge  T

it has no mass  F

it has a negative charge  F

it is inside the nucleus  ...it is part OF the nucleus.

it is the same as the atomic number  T

it is the same as the number of neutrons  F

75% of the isotopes have a mass ima just guess cuz i dunno about this one...i think it matters on the atom element.

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3 0
3 years ago
Explain how scientists use balanced chemical equations and molar mass concepts to represent reactions and account for the amount
konstantin123 [22]

Explanation:

Scientists most especially chemists use the mole concepts through balanced chemical equations and molar masses to represent chemical reactions and account for the amount of substances.

The mole concept entails finding molar relationships between reactants and products in a chemical reaction. Mole connects difference chemical parameters and it is used in quantitative analysis of chemical reaction.

  • First, we work from the known to the unknown.
  • The known is the specie whose mass or number of moles is given.

  Number of moles  = \frac{mass}{molar mass}

  • After obtaining the number of moles, then go ahead to compared using the balanced reaction with that of the unknown.
  • Then from them find the mass of the unknown.  
6 0
3 years ago
Consider the following reaction:
noname [10]

Answer:

26.6

Explanation:

Step 1: Calculate the molar concentrations

We will use the following expression.

M = mass solute / molar mass solute × liters of solution

[CO]i = 26.6 g / (28.01 g/mol) × 5.15 L = 0.184 M

[H₂]i = 2.36 g / (2.02 g/mol) × 5.15 L = 0.227 M

[CH₃OH]e = 8.63 g / (32.04 g/mol) × 5.15 L = 0.0523 M

Step 2: Make an ICE chart

        CO(g) + 2 H₂(g) ⇄ CH₃OH(g)

I        0.184      0.227           0

C         -x           -2x             +x

E     0.184-x   0.227-2x        x

Since [CH₃OH]e = x, x = 0.0523

Step 3: Calculate all the concentrations at equilibrium

[CO]e = 0.184-x = 0.132 M

[H₂]e = 0.227-2x = 0.122 M

[CH₃OH]e = 0.0523 M

Step 4: Calculate the equilibrium constant (Kc)

Kc = [CH₃OH] / [CO] [H₂]²

Kc = 0.0523 / 0.132 × 0.122² = 26.6

8 0
3 years ago
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