Answer:
Given that
speed u=4*10^6 m/s
electric field E=4*10^3 N/c
distance b/w the plates d=2 cm
basing on the concept of the electrostatices
now we find the acceleration b/w the plates to find the horizontal distance traveled by the electron when it hits the plate.
acceleration a=qE/m=
=
m/s
now we find the horizontal distance traveled by electrons hit the plates
horizontal distance
![X=u[2y/a]^{1/2}](https://tex.z-dn.net/?f=X%3Du%5B2y%2Fa%5D%5E%7B1%2F2%7D)
=![4*10^6[2*2*10^{-2}/7*10^{14}]^{1/2}](https://tex.z-dn.net/?f=4%2A10%5E6%5B2%2A2%2A10%5E%7B-2%7D%2F7%2A10%5E%7B14%7D%5D%5E%7B1%2F2%7D)
=
= 3 cm
Answer:
dart
Explanation:
dart and sun and water so that the plant be okay
Answer:2800000j
Explanation:
For us to know the kinetic energy of the vehicle,
Where m is the mass
And v is the velocity
Then, K.E=1/2mv^2
While, K.E=1/2×3500×40^2
Therefore, our answer will now be
K.E=2800000j
Answer:
Wt = 26.84 [N]
Explanation:
In order to solve this problem we must use the definition of work in physics. Which tells us that this is equal to the product of force by distance.
In this case, we must sum the works of the force applied by the box and the friction force that also acts on the box.
The friction force is defined as the product of the normal force by the coefficient of friction.
f = N*μ
where:
N = normal force = m*g [N] (units of Newtons)
m = mass = 72 [kg]
g = gravity acceleration = 9.81 [m/s²]
f = friction force [N]
μ = friction coefficient = 0.21
f = 72*9.81*0.21
f = 148.32 [N]
Now the total work:
Wt = WF - Wf
where:
Wt = total work [J] (units of Joules)
WF = work by the pushing force [J]
Wf = work done by the friction force [J]
Wt = (160*2.3) - (148.32*2.3)
Wt = 26.84 [N]
Note: The friction force exerts a negative work, because this force is acting in opposite direction to the movement, therefore the negative sign.
