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zhuklara [117]
3 years ago
11

3. You are to determine the power rating of the motor in an elevator system. The elevator (with a full load) weights 1700 kg and

is required to move upward 3 m/sec at constant speed. The lifting mechanism is 90% efficient (i.e., 10% of the power generated by the motor is wasted in the mechanism, e.g., for overcoming friction). What is the minimum output power rating in HP of the motor that meets the requirement?
Physics
1 answer:
Talja [164]3 years ago
3 0

Answer:

3. You are to determine the power rating of the motor in an elevator system. The elevator (with a full load) weights 1700 kg and is required to move upward 3 m/sec at constant speed. The lifting mechanism is 90% efficient (i.e., 10% of the power generated by the motor is wasted in the mechanism, e.g., for overcoming friction). What is the minimum output power rating in HP of the motor that meets the requirement?The Elevator (with A Full Load) Weights 2000 Kg And Is Required To Move Upward 3 M/sec At Constant Speed. The Lifting Mechanism Is 85% Efficient (i.e., 15% Of The Power Generated By The Motor Is Wasted In The Mechanism, E.g., For Overcoming Friction).

Explanation:

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Several motorboats with the same mass are used in an experiment. The forces of the different motors versus their accelerations a
Yuliya22 [10]

Answer:

C. the velocity

Explanation:

7 0
3 years ago
A 2.9-kg cart is rolling across a frictionless, horizontal track toward a 1.4-kg cart that is held initially at rest. The carts
VikaD [51]

Answer:

The question is incomplete. I will assume you intend to find the total momentum of the two carts during collision. Therefore, we can use the conservation of momentum principle to get the total momentum at a certain instant before collision.

Explanation:

The conservation of momentum principle states that the initial net momentum of two bodies before collision is equal to the final net momentum after collision.

In this case, let's denote the rolling cart as <em>'a'</em> and the stationary cart as <em>'b'</em>.

Momentum, P = MaVa +MbVb

P=(2.9)(+4.7) + (1.4)(-1.9)\\P= 13.68 + (-2.66)\\P= 13.68-2.66\\P=+11.02 Kg.m/s

Therefore, the total momentum before collision is 11.02 Kg.m/s.

6 0
3 years ago
A dumbbell-shaped object is composed by two equal masses, m, connected by a rod of negligible mass and length r. If I_1 is the m
Paraphin [41]

Answer:

I2>I1

Explanation:

This problem can be solved by using the parallel axis theorem. If the axis of rotation of a rigid body (with moment of inertia I1 at its center of mass) is changed, then, the new moment of inertia is gven by:

I_2=I_{1}+Md^2

where M is the mass of the object and d is the distance of the new axis to the axis of the center of mass.

It is clear that I2 is greater than I1 by the contribution of the term Md^2.

I2>I1

hope this helps!!

8 0
3 years ago
Determine the gravitational potential energy, in kJ, of 3 m3 of liquid water at an elevation of 40 m above the surface of Earth.
melomori [17]

Explanation:

We will calculate the gravitational potential energy as follows.

                 P.E_{1} = mgz_{1}

       P.E_{1} = (\rho V)gz_{1}    

                    = 1000 kg/m^{3} \times 3 m^{3} \times 9.7 \times 40 m

                    = 1164000 J

or,                = 1164 kJ         (as 1 kJ = 1000 J)

Now, we will calculate the change in potential energy as follows.

             \Delta P.E = mg(z_{2} - z_{1})

                         = \rho \times V \times g (z_{2} - z_{1})

                         = 1000 \times 3 \times 9.7 (10 - 40)m

                         = -873000 J

or,                      = -873 kJ

Thus, we can conclude that change in  gravitational potential energy is -873 kJ.

4 0
2 years ago
What is the astronomy made of
vekshin1

Answer:

Astronomers like to call all material made up of protons, neutrons and electrons "baryonic matter". Until about thirty years ago, astronomers thought that the universe was composed almost entirely of this "baryonic matter", ordinary atoms.

Explanation:

4 0
3 years ago
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