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slavikrds [6]
3 years ago
5

How do you make a iPad I can text and stuff and don't understand how

Physics
2 answers:
dmitriy555 [2]3 years ago
8 0

Answer:

On your iPhone, go to Settings > Messages > Send & Receive. Add a check to both your phone number and email address. Then go to Settings > Messages > Text Message Forwarding and enable the device or devices that you want to forward messages to. Look for a code on the Mac, iPad, or iPod touch that you enabled.

Explanation:

I guess

tigry1 [53]3 years ago
4 0
Circuit board stuff
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If a car is traveling at a speed of 45 miles per hour, how far<br>can it travel in 40 minutes?​
dusya [7]

Answer:

30 miles

Explanation:

<u>Step 1:</u>

Divide -> 45/60= .75 miles/minute

<u>Step 2:</u>

Multiply -> .75 x 40= 30

3 0
3 years ago
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If you lift a five pound object 18 inches how many joules of energy did yo use?
kogti [31]
The work is 90 as 5 times 18

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3 years ago
A distant large asteroid is detected that might pose a threat to Earth. If it were to continue moving in a straight line at cons
Vlada [557]

Answer:

The minimum speed required is 5.7395km/s.

Explanation:

To escape earth, the kinetic energy of the asteroid must be greater or equal to its gravitational potential energy:

K.E\geq P.E

or

\dfrac{1}{2}mv^2 \geq  G\dfrac{Mm}{R}

where m is the mass of the asteroid, R= 24,000,000\:m is its distance form earth's center, M = 5.9*10^{24}kg is the mass of the earth, and G = 6.7*10^{-11}m^3/kg\: s^2 is the gravitational constant.

Solving for v we get:

v \geq \sqrt{\dfrac{2GM}{R} }

putting in numerical values gives

v \geq \sqrt{\dfrac{2(6.7*10^{-11})(5.9*10^{24})}{(24,000,000)} }

\boxed{v\geq 5739.5m/s}

in kilometers this is

v\geq5.7395m/s.

Hence, the minimum speed required is 5.7395km/s.

5 0
3 years ago
If an ideal gas does not exist then why laws were stated?
mihalych1998 [28]
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If a current-carrying wire is in a magnetic field, in what direction will a force be exerted on the wire?.
astraxan [27]

Answer:

The magnetic force on a current-carrying wire is perpendicular to both the wire and the magnetic field with direction given by the right hand rule.

4 0
2 years ago
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