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Charra [1.4K]
3 years ago
9

a wire carrying 1.5 A passes through a 48 mT magnetic field the wire is peremndicular to the field and makes a quarter circle tu

rn radius 21 cm in the dield regeion. Find the magnitude and direction of the magnetic force
Physics
1 answer:
professor190 [17]3 years ago
8 0

Answer:

Explanation:

Wire is in the form of an arc of the size of a quarter of a circle. The distance between its two end

=√2 x 21 cm

= 29.7 cm

= 29.7 x 10⁻² m

Force on the arc in the magnetic field will be same as the straight line meeting its two ends.

Force = BIL

= 48 x10⁻³ x  1.5 x 29.7 x 10⁻²

= 2138.4 x 10⁻⁵ N.

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