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borishaifa [10]
3 years ago
13

The figure shows an uncharged conducting cubic shell and a positive point charge Q outside the shell. There are two lettered poi

nts W and X inside the shell where the electric field can be measured. The electric field at points W and X are EW and EX, respectively. Point W is at the center of the cubic shell. Outside the shell are points Y and Z where the charge Q can be placed. All four points are along the same line. Which of the following statements is correct?
If the point charge is placed at point Y , EW>EX .


Answer A: If the point charge is placed at point Y , E sub W is greater than E sub X .


Answer B: If the point charge is placed at point Y , E sub W is less than E sub X .


Answer C: If the point charge is placed at point Z , E sub W is greater than E sub X .


Answer D: If the point charge is placed at point Z , E sub W is less than E sub X .


Answer E: If the point charge is placed at point Z , E sub W is equal to E sub X .

Physics
1 answer:
Nataliya [291]3 years ago
4 0

If the point charge is placed at point E_W is equal to E_X.

<h3>Electric field inside a conducting cubic shell</h3>

The electric field inside a conducting cubic shell is zero. When a point charge is placed outside the shell, the electric field outside the shell is greater than the electric field inside the shell which is zero.

We can deduce the following;

  • Electric field inside the shell is zero, thus E_W = E_X =0
  • Electric field outside the shell is greater than electric field inside the shell

Thus, the only correct statement is, If the point charge is placed at point E_W is equal to E_X.

Learn more about electric field inside a shell here: brainly.com/question/539905

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You jump off a platform 134 m above the Neuse River. After you have free-fallen for the first 40 m, the bungee cord attached to
omeli [17]

Answer:

The acceleration at lowest point is 19.62 m/s^2

Explanation:

Conservation of energy is an concept in which it is stated that the energy of an isolated object remains the same. Energy changes from one form to another.

Lets Assume

Constant of string is K

By using the conservation of energy we will have the following equation

1/2 x 80^2 x K = m x 9.81 x 120

3200 K =  1177.2 m

K = 1177.2 m / 3200

K = 0.368 m

At the lowest point we will have

a = ( K x X - m x g ) / m

a = ( 0.368 m x 80 - m x 9.81 ) / m

a = 19.62 m / s^2

So, the acceleration at lowest point is 19.62 m/s^2

7 0
3 years ago
Read 2 more answers
In a manufacturing process, a large, cylindrical roller is used to flatten material fed beneath it. The diameter of the roller i
kotykmax [81]

The maximum angular speed of the roller is 3.47rad/a,  

the maximum tangential speed of the point an the rim of the roller is 1.47m/s,

the time t should the driven force be removed from the roller so that the roller does not reverse its direction of rotation is t = 2.78s,

5.4 rotation has the roller turned between t=0 and the time found in part c

<h3>What does tangential speed refer to?</h3>

Any item moving along a circular path has a linear component to its speed called tangential velocity. An object's velocity is always pointed tangentially when it travels in a circle at a distance r from the center. The word for this is tangential velocity.

To calculate the tangential speed, divide the circumference by the time required to complete one spin. For instance, if it takes 12 seconds to complete one rotation, divide 18.84 by 12 to get 1.57 feet per second as the tangential velocity.

(a) angular speed w = dθ/dt = 5t - 1.8t^2

dw/dt = 5 - 3.6t = 0 for max w

so max w occurs at t = 5/3.6 s = 1.39s

so w max = 5*1.39 - 1.8*(1.39)^2 = 3.47 rad/s

(b) tangential speed v = r*w

r = D/2 = 0.5m

so v = 0.5*w = 1.74 m/s

(c) w is positive until 5t = 1.8t^2

so t = 5/1.8s = 2.78s (or t = 0 invalid)

After t = 2.87s, w is negative (starts reversing direction of rotation)

Driving force would actually have to be removed some time before t=2.78s because the roller can't stop instantaneously, but insufficient info to calculate this.

(d) Up to t = 2.78s, θ = 2.5*(2.78)^2 - 0.6*(2.78)^3 rad = 33.95 rad = 5.40 rotations

Therefore,

A) 3.47rad/a

B) 1.47m/s

C) t = 2.78s

D) 5.4 rotation

To learn more about tangential speed, refer to:

brainly.com/question/19660334

#SPJ4

4 0
2 years ago
An air gun fires 2 gram pellets at 60 m/s at a 45 gram golfball initially at rest. The pellets rebound at a speed 40 m/s and are
snow_lady [41]

Answer:

0.16 kgm/s

Explanation:

m_1 = Mass of pellet = 2 g

m_2 = Mass of golf ball = 45 g

u_1 = Initial Velocity of pellet  = 60 m/s

u_2 = Initial Velocity of golf ball = 0 m/s

v_1 = Final Velocity of pellet = 40 m/s

v_2 = Final Velocity of golf ball

In this system the linear momentum is conserved

m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow m_2v_2=m_1u_1+m_2u_2-m_1v_1\\\Rightarrow m_2v_2=0.002\times 60+0-0.002\times 40\\\Rightarrow m_2v_2=0.04

As the golf ball is being shot 4 times every second the momentum delivered to the golf ball each second is 4\times 0.04=0.16\ kgm/s

8 0
3 years ago
A runner completes a 10 km run in about 45 minutes. What was the runner’s speed in km/h?
OlgaM077 [116]

Answer: 12.5 km/s

I don't really know how to explain this, but here is your answer.

5 0
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What average net force is required to stop a 4.5 kg bowling ball,initially at rest, accelerated for 6 seconds over a distance of
tatuchka [14]

Answer:

32

Explanation:

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