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borishaifa [10]
3 years ago
13

The figure shows an uncharged conducting cubic shell and a positive point charge Q outside the shell. There are two lettered poi

nts W and X inside the shell where the electric field can be measured. The electric field at points W and X are EW and EX, respectively. Point W is at the center of the cubic shell. Outside the shell are points Y and Z where the charge Q can be placed. All four points are along the same line. Which of the following statements is correct?
If the point charge is placed at point Y , EW>EX .


Answer A: If the point charge is placed at point Y , E sub W is greater than E sub X .


Answer B: If the point charge is placed at point Y , E sub W is less than E sub X .


Answer C: If the point charge is placed at point Z , E sub W is greater than E sub X .


Answer D: If the point charge is placed at point Z , E sub W is less than E sub X .


Answer E: If the point charge is placed at point Z , E sub W is equal to E sub X .

Physics
1 answer:
Nataliya [291]3 years ago
4 0

If the point charge is placed at point E_W is equal to E_X.

<h3>Electric field inside a conducting cubic shell</h3>

The electric field inside a conducting cubic shell is zero. When a point charge is placed outside the shell, the electric field outside the shell is greater than the electric field inside the shell which is zero.

We can deduce the following;

  • Electric field inside the shell is zero, thus E_W = E_X =0
  • Electric field outside the shell is greater than electric field inside the shell

Thus, the only correct statement is, If the point charge is placed at point E_W is equal to E_X.

Learn more about electric field inside a shell here: brainly.com/question/539905

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2 years ago
Choose all that apply. Which of the following questions could you answer by measuring length? 1 How tall are you? 2How far is it
horsena [70]

The correct options are:

1 How tall are you?

2How far is it from your house to your school?

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All these measurements involve to measure a length. Instead, the other two options involve to measure different physical quantities; for instance, the question

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8 0
4 years ago
An elevator and its load have a combined mass of 1650 kg. Find the tension in the supporting cable when the elevator, originally
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Answer:

Tension in the supporting cable is = 4,866 N ≅4.9 KN

Explanation:

First of all, we need to understand that tension is a force, so the motion law

F = Ma applies perfectly.

From Newtons third law of motion, action and reaction are equal and opposite. This means that the force experienced by the elevator, is equal to the tension experienced by the spring.

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Mass of load = 1650 kg

Acceleration of load = ?

The acceleration of the load can be obtained by diving the change in velocity by the time taken. But we need to know the time taken for the motion to 41 m.

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Note: Final velocity is = 0 since the body came to a rest.

Acceleration = \frac{11 - 0 m/s}{3.73s} = 2.95m/s^{2}

Force acting on the cable = mass of elevator × acceleration of elevator

= 1650 × 2.95 = 4869.5 kg ≅ 4.9 KN

6 0
3 years ago
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