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borishaifa [10]
2 years ago
13

The figure shows an uncharged conducting cubic shell and a positive point charge Q outside the shell. There are two lettered poi

nts W and X inside the shell where the electric field can be measured. The electric field at points W and X are EW and EX, respectively. Point W is at the center of the cubic shell. Outside the shell are points Y and Z where the charge Q can be placed. All four points are along the same line. Which of the following statements is correct?
If the point charge is placed at point Y , EW>EX .


Answer A: If the point charge is placed at point Y , E sub W is greater than E sub X .


Answer B: If the point charge is placed at point Y , E sub W is less than E sub X .


Answer C: If the point charge is placed at point Z , E sub W is greater than E sub X .


Answer D: If the point charge is placed at point Z , E sub W is less than E sub X .


Answer E: If the point charge is placed at point Z , E sub W is equal to E sub X .

Physics
1 answer:
Nataliya [291]2 years ago
4 0

If the point charge is placed at point E_W is equal to E_X.

<h3>Electric field inside a conducting cubic shell</h3>

The electric field inside a conducting cubic shell is zero. When a point charge is placed outside the shell, the electric field outside the shell is greater than the electric field inside the shell which is zero.

We can deduce the following;

  • Electric field inside the shell is zero, thus E_W = E_X =0
  • Electric field outside the shell is greater than electric field inside the shell

Thus, the only correct statement is, If the point charge is placed at point E_W is equal to E_X.

Learn more about electric field inside a shell here: brainly.com/question/539905

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Answer:

(1) Exercise should be painful in order for it to be beneficial. FALSE

(2) Proper progression involves a gradual increase in the level of exercise. TRUE

(3) Exercising on a regular, consistent basis provides you with the best results. TRUE

Explanation:

(1) It is a false statement because whenever we do exercise, it should not be painful, it should be comfortable to some extent for a person, if it will be painful then it means one cant get the true and genuine benefit from the exercise.

(2) It is very much true because one must keep on increasing the level of his/her exercise gradually with the passage of time, it will make his/her body synchronized with the exercise properly.

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3 years ago
You have a resistor of resistance 200 ? and a 6.00-?F capacitor. Suppose you take the resistor and capacitor and make a series c
Ne4ueva [31]

Answer:

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4 0
3 years ago
A pencil rolls horizontally of a 1 meter high desk and lands .25 meters from the base of the desk. How fast was the pencil rolli
vovikov84 [41]

Answer: 0.55 m/s

Explanation:

This situation is related to projectile motion (also called parabolic motion), where the main equations are as follows:

x=V_{o} cos\theta t (1)

y=y_{o}+Vo sin \theta t + \frac{g}{2}t^{2} (2)

Where:

x=0.25 m is the horizontal displacement of the pencil

V_{o} is the pencil's initial velocity

\theta=0\° since we are told the pencil rolls <u>horizontally</u> before falling

t is the time since the pencil falls until it hits the ground

y_{o}=1 m  is the initial height of the pencil

y=0  is the final height of the pencil (when it finally hits the ground)

g=-9.8m/s^{2}  is the acceleration due gravity, always acting vertically downwards

Begining with (1):

x=V_{o} cos(0\°) t (3)

x=V_{o}t (4)

Finding t from (2):

0=1 m+ \frac{-9.8m/s^{2}}{2}t^{2} (5)

t=\sqrt{\frac{-2y_{o}}{g}} (6)

Substituting (6) in (4):

x=V_{o}\sqrt{\frac{-2y_{o}}{g}} (7)

Isolating V_{o}:

V_{o}=\frac{x}{\sqrt{\frac{-2y_{o}}{g}}} (8)

V_{o}=\frac{0.25 m}{\sqrt{\frac{-2(1 m)}{-9.8m/s^{2}}}} (9)

Finally:

V_{o}=0.55 m/s

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