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Rzqust [24]
3 years ago
11

Convert 56 kilometers to inches

Physics
1 answer:
svlad2 [7]3 years ago
7 0
The conversion for km to inches is:

1km=39370.1in

Now we can solve for 56 km..

56km=39370.1*56
56km=<span> 2204725.6in

Answer=2,204,725.6in</span>
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3. A student determined the Kf of t-butyl alcohol using tap water instead of distilled or deionized water. Describe the problems
eduard

Answer:

The Kf (Freezing Point Depression Constant) is been affect by freezing point among many other factor now using tap water for this experiment would mean that there would be salt present in the solution in that tap water is usually added fluoride which would react with the natural potassium present in the water to form a salt this salt would depress the freezing point of the water hence the value of Kf would be bigger that the actual value

Explanation:d

3 0
3 years ago
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If g were 15 instead of 9.81, what would your quads look like?
Jlenok [28]

Answer:

Quads will have more energy

Explanation:

If the acceleration due to gravity increases from 9.81 to 15, then the velocity will increase as the rate of changing velocity i.e acceleration has increased from 9.81 to 15 m/s^2

With increase of velocity, the energy and force will also increase. Hence, the squad will require/have higher energy.

5 0
2 years ago
A 102 kg football player runs at a speed of 8 m/s to sack the quarterback. What is
leva [86]

The mass of the quarterback is 61.2 kg.

Explanation:

mass of the football player = m1 = 102 kg

mass of the quarterback = m2 = ?

velocity of the football player = v1 = 8 m/s

According to the law of conservation of momentum:

The total momentum of a system before and after the collision remains constant. Assuming the situation as an isolated system which is not affected by any external factors, we have:

m₁v₁ + m₂v₂ = (m₁+m₂)V

Here, we need to find m₂.

We assume that the quarterback is standing still when he is attacked by the football player so v₂ = 0 m/s

After the collision both of them fall to the ground with a velocity of 5 m/s so V = 5 m/s

102(8) + m2(0) = (102 + m2)(5)\\816 + 0 = (102 + m2)(5)\\816/5 = 102 + m2\\163.2 - 102 = m2\\m2 = 61.2 kg

Keywords: momentum, velocity, law of conservation of momentum

Learn more about Law of Conservation of Momentum from brainly.com/question/7538238

#learnwithBrainly

3 0
3 years ago
A goose with a mass of 2.0 kg strikes a commercial airliner with a mass of 160,000 kg head-on. Before the collision, the goose w
Goryan [66]

Answer:

The change in momentum of the goose during this interaction is 33.334 m/s

Explanation:

Given;

mass of goose, m₁ = 2.0 kg

mass of commercial airliner, m₂ = 160,000 kg

initial velocity of the bird, u₁ = 60 km/hr  = 16.667 m/s

initial velocity of the airliner, u₂ = 870 km/hr = 241.667 m/s

Change in momentum is given as;

ΔP = mv - mu

where;

u is the initial velocity of the bird

v is the final velocity of the bird

Apply the principle of conservation of linear momentum;

Total momentum before collision = Total momentum after collision

m₁u₁ + m₂u₂ = v(m₁ + m₂)

where;

v is the final velocity of bird and airliner after collision;

(2 x 16.667) + (160,000 x 241.667) = v (2 + 160,000)

38,666,753.334 = 160,002v

v = 38,666,753.334 / 160,002

v = 241.664 m/s

Thus, the final velocity of the bird is negligible compared to final  velocity of the airliner.

ΔP = mv - mu

ΔP = m(v - u)

ΔP = 2(0 - 16.667)

ΔP = -33.334 m/s

The negative sign implies a deceleration of the bird after the impact.

Therefore, the change in momentum of the goose during this interaction is 33.334 m/s

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Yes it was then a red left label
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