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3 years ago

PLEASEEEEE PLEASEEEEE ANSWER THIS QUESTION ILL GIVE BRAINLIEST AND 15 POINTS

Chemistry

2 answers:

jek_recluse [69]3 years ago

8 0

Answer:

C. Sedimentary

Fossils, the preserved remains of animal and plant life, are mostly found embedded in sedimentary rocks. Of the sedimentary rocks, most fossils occur in shale, limestone and sandstone. Earth contains three types of rocks: metamorphic, igneous and sedimentary.

**google :)

ivann1987 [24]3 years ago

4 0

Answer:

The answer is C. Sedimentary

Explanation:

Because sedimentary rock is formed from layers of rock over time, fossils are more likely to appear in that particular type of rock.

I hope this helps! :)

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A sample of aluminum, which has a specific heat capacity of , is put into a calorimeter (see sketch at right) that contains of w

Oksanka [162]

Complete Question

A sample of aluminum, which has a specific heat capacity of 0.897 JB loc ! is put into a calorimeter (see sketch at right) that contains 200.0 g of water. The aluminum sample starts off at 85.6 °C and the temperature of the water starts off at 16.0 °C. When the temperature of the water stops changing it's 20.1 °C. The pressure remains constant at 1 atm. Calculate the mass of the aluminum sample.

Answer:

$M=58g$

Explanation:

From the question we are told that:

Heat Capacity $H=0.897$

Mass of water $M=200g$

Initial Temperature of Aluminium $T_a=85.6$

Initial Temperature of Water $T_{w1}=16.0$

Final Temperature of Water $T_{w2}=16.0$

Generally

Heat loss=Heat Gain

Therefore

$M*0.897*(85.6-20.1) =200*4.184*(20.1-16)$

$M=58g$

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3 years ago

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Answer:

barium

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Explanation:

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3 years ago

Sodium thiosulfate, na2s2o3, is used as a "fixer" in black and white photography. identify the reducing agent in the reaction of

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3 years ago

If 0.092J of heat causes a 0.267 degree C temperature change, what mass of water is present?

Thepotemich [5.8K]

Answer:

0.082g

Explanation:

The following data were obtained from the question:

Heat (Q) = 0.092J

Change in temperature (ΔT) = 0.267°C

Specific heat capacity (C) of water = 4.184J/g°C

Mass (M) =..?

Thus, the mass of present can be obtained as follow:

Q = MCΔT

0.092 = M x 4.184 x 0.267

Divide both side by 4.184 x 0.267

M = 0.092 / (4.184 x 0.267)

M = 0.082g

Therefore, mass of water was present is 0.082.

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3 years ago