All categories

2 years ago

What best describes the angle between a changing electric field and the electromagnetic wave produced by it?

Physics

1 answer:

mel-nik [20]2 years ago

3 0

The correct answer here is Option A, always equal to a right angle.

Keep in mind that the phase difference that exists between the electric field and the magnetic wave is 90 °, this means that the changing electric field and the electromagnetic wave are always perpendicular and will be forming a right angle.

You might be interested in

The drawing shows two frictionless inclines that begin at ground level (h = 0 m) and slope upward at the same angle θ. One track

Elena L [17]

Answer:

a). $H=2.45m$

b). $H_{max}=1.94m$

Explanation:

For the block that stays on the track, its maximal height is attained when all of the kinetic energy is converted to potential energy

a).

The height for the block on the longer track can by find using this equation:

$\frac{1}{2}*m*v_o^2=m*g*H$

Cancel the mass as a factor in each element in the equation

$H=\frac{v_o^2}{2*g}$

$H=\frac{(6.94m/s)^2}{2*9.8m/s^2}$

$H=2.45m$

b).

The other lost some kinetic energy so, use a projectile motion to determine the total height for the other bock:

$E_k=E_p$

$E_k=m*g*H_1$

$E_k=\frac{1}{2}*m*v_o^2-\frac{1}{2}*m*v^2$

$m*g*H_1=\frac{1}{2}*m*(v_o^2-v^2)$

Solve to v'

$v^2=v_o^2-2*g*H_1$

$v=\sqrt{v_o^2-2*g*H_1}=\sqrt{(6.94m/s)^2-2*9.8m/s^2*1.25m}$

$v=4.8m/s$

$H_{max}=H_1+\frac{v^2*sin(50)}{2*g}=1.25m+\frac{(4.8m/s)^2*sin(50)}{2*9.8m/s^2}$

$H_{max}=1.94m$

8 0

3 years ago

Read 2 more answers

a 20 ft shipping container on a cargo ship has a mass of 24000 kg and a volume of 33.2m3. what is the density of the shipping co

Ira Lisetskai [31]

Answer:

722.89

Explanation:

mass=24000kg

volume=33•2

density=?

now,

density=mass/volume

=24000/33•2

=722•89

density=722•89 kg/m^3

3 0

3 years ago

Why do people cover their flowers on a cool night. Think about radiation absorption conduction and temperature

Blababa [14]

When the temperature lowers the plants can freeze and die. One way to prevent that is to cover the plants so they dont freeze

3 0

2 years ago

A particle leaves the origin with a speed of 3 106 m/s at 38 degrees to the positive x axis. It moves in a uniform electric fiel

Salsk061 [2.6K]

Answer:

If the particle is an electron $E_y = 3.311 * 10^3 N/C$

If the particle is a proton, $E_y = 6.08 * 10^6 N/C$

Explanation:

Initial speed at the origin, $u = 3 * 10^6 m/s$

$\theta = 38^0$ to +ve x-axis

The particle crosses the x-axis at , x = 1.5 cm = 0.015 m

The particle can either be an electron or a proton:

Mass of an electron, $m_e = 9.1 * 10^{-31} kg$

Mass of a proton, $m_p = 1.67 * 10^{-27} kg$

The electric field intensity along the positive y axis $E_y$ , can be given by the formula:

$E_y = \frac{2 m u^2 sin \theta cos \theta}{qx} \\$

If the particle is an electron:

$E_y = \frac{2 m_e u^2 sin \theta cos \theta}{qx} \\$

$E_y = \frac{2 * 9.1 * 10^{-31} * (3*10^6)^2 *(sin38)( cos38)}{1.6*10^{-19} * 0.015} \\$

$E_y = 3311.13 N/C\\E_y = 3.311 * 10^3 N/C$

If the particle is a proton:

$E_y = \frac{2 m_p u^2 sin \theta cos \theta}{qx} \\$

$E_y = \frac{2 * 1.67 * 10^{-27} * (3*10^6)^2 *(sin38)( cos38)}{1.6*10^{-19} * 0.015} \\$

$E_y = 6.08 * 10^6 N/C$

8 0

2 years ago

An average human weighs about 600 N

NemiM [27]

Answer:

The distance between them, x = 5809.47 m

Explanation:

Given,

The average weight of a human, w = 600 N

The charge carried by the humans, q = 1.5 C

If 600 N of force acts between two opposite charges, the distance between the charges can be derived from the Coulomb's laws of force,

<em> $F=\frac{1}{4\pi\epsilon_{0}}\frac{qq}{x^{2}}$ </em>

Where,

$\frac{1}{4\pi\epsilon_{0}}$ = 9 x 10⁹ N m² C⁻²

Therefore

x² = 9 x 10⁹ X 1.5² / 600

= 33750000

x = 5809.46 m

Hence, the distance between the humans should be, x = 5809.47 m

4 0

3 years ago