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RideAnS [48]
4 years ago
6

Focus Question: What are SI units, and why are they used?

Physics
1 answer:
igomit [66]4 years ago
3 0

Answer:

a system of physical units ( SI units ) based on the metre, kilogram, second, ampere, kelvin, candela, and mole, together with a set of prefixes to indicate multiplication or division by a power of ten.

Explanation:

The problem here was not the error; it was the failure of NASA's systems engineering, and the checks and balances in our processes, to detect the error. That's why we lost the spacecraft.

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True or false day and night are caused by earths rotation
olga2289 [7]
True because it is day in one part and night in the other
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A new planet is discovered orbiting a distant star. Observations have confirmed that the planet has a circular orbit with a radi
Mariulka [41]

Answer:

Mass of star is 1.31\times10^{35} kg.

Explanation:

The cube of orbital radius is equal to the square of its orbital time period is known as Kepler's law.

T^{2} = (\frac{4\pi^{2} }{GM})r^{3}          .....(1)

Here T is time period, r is orbital radius, G is universal gravitational constant and M is the mass of the star.

According to the problem,

Time period, T = 109 days = 109 x 24 x 60 x 60 s = 9.41 x 10⁶ s

Orbital radius, r = 18 AU = 18 x 1.496 x 10¹¹ m = 2.70 x 10¹² m

Gravitational constant, G = 6.67 x 10⁻¹¹ m³ kg⁻¹ s⁻²

Substitute these values in equation (1).

(9.41\times10^{6}) ^{2} = (\frac{4\pi^{2} }{6.67\times10^{-11}\times M})(2.70\times10^{12}) ^{3}

M = 1.31\times10^{35} kg

3 0
3 years ago
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madreJ [45]

Answer:

From C to D, kinetic energy is transformed into

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4 0
3 years ago
a projectile whose masss is 10g is fired directly upward from ground level with an initial velocity of 1000m/s neglecting the ef
sammy [17]

Answer:

<em>The speed of the projectile when it impacts the ground is 1000 m/s</em>

Explanation:

<u>Vertical Launch</u>

When an object is launched vertically and upwards it starts to move at an initial speed vo, then the acceleration of gravity makes that speed to reduce until it reaches 0. The object has reached its maximum height. Then, it starts to move downwards in free fall, with initial speed zero and gradually increasing it until it reaches the ground level. We will demonstrate that the speed it has when impacts the ground is the same (and opposite) as the initial speed vo.

The speed when the object is moving upwards is given by

v_f=v_o-g.t

The time it takes to reach the maximum height is when vf=0, i.e.

0=v_o-g.t

solving for t

\displaystyle t=\frac{v_o}{g}

The maximum height reached is

\displaystyle y=\frac{gt^2}{2}=\frac{v_o^2}{2g}

Then, the object starts to fall. The object's height is given by

\displaystyle y=\frac{v_o^2}{2g}-\frac{gt'^2}{2}

where t' is the time the object has traveled downwards. The height will be 0 again when

\displaystyle \frac{v_o^2}{2g}=\frac{gt'^2}{2}

Solving for t'

\displaystyle t'=\frac{v_o}{g}

We can see the time it takes to reach the maximum height is the same it takes to return to ground level. Of course, the speed when it happens is

v_f=g.t'=v_o

Thus, the speed of the projectile when it impacts the ground is 1000 m/s

4 0
4 years ago
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