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muminat
3 years ago
13

Ice of mass 5 g at 0 °C melts to water at 0 °C.

Physics
1 answer:
amid [387]3 years ago
5 0

Answer:

Q=1670J

Explanation:

Mass of ice: m=5g=0.005kg

Latent heat: lambda=3.34×10⁵J/kg

Heat received by ice: Q=m×lambda

Q=0.005×3.34×10⁵=5×334=1670J

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Calculate the centripetal force on the end of a 100 m (radius) wind turbine blade that is rotating at 0.5 rev/s. Assume the mass
Alja [10]

Answer:

3947.6 N

Explanation:

Centripetal Force: This is the force that tend to moves a body towards the center of a circle during circular motion.

The formula for centripetal force is

F = mω²r ........................ Equation 1

Where F = Centripetal force, ω = angular velocity, r = radius.

Where π = 3.1415

Given: m = 4 kg, ω = 0.5 rev/s = (0.5×2π) rad/s = 3.1415 rad/s, r = 100 m.

Substitute into equation 1

F = 4(3.1415)²(100)

F = 3947.6 N

Hence the centripetal force on the turbine blade = 3947.6 N

6 0
3 years ago
A comet is traveling through space with speed 3.01 ✕ 104 m/s when it encounters an asteroid that was at rest. The comet and the
Tcecarenko [31]

Answer: 8.493(10)^{-3} m/s

Explanation:

According to the conservation of linear momentum principle, the initial momentum p_{i} (before the collision) must be equal to the final momentum p_{f} (after the collision):

p_{i}=p_{f} (1)

In addition, the initial momentum is:

p_{i}=m_{1}V_{1}+m_{2}V_{2} (2)

Where:

m_{1}=1.71(10)^{14} kg is the mass of the comet

m_{2}=6.06(10)^{20} kg is the mass of the asteroid

V_{1}=3.01(10)^{4} m/s is the velocity of the comet, which is positive

V_{2}=0 m/s is the velocity of the asteroid, since it is at rest

And the final momentum is:

p_{f}=(m_{1}+m_{2})V_{f} (3)

Where:

V_{f} is the final velocity

Then :

m_{1}V_{1}+m_{2}V_{2}=(m_{1}+m_{2})V_{f} (4)

Isolating V_{f}:

V_{f}=\frac{m_{1}V_{1}}{m_{1}+m_{2}} (5)

V_{f}=\frac{(1.71(10)^{14} kg)(3.01(10)^{4} m/s)}{1.71(10)^{14} kg+6.06(10)^{20} kg}

Finally:

V_{f}=8.493(10)^{-3} m/s This is the final velocity, which is also in the positive direction.

8 0
3 years ago
a ray of light incident on a mirror, at an angle of 45°. Another mirror is placed at an angle of 45° to the first ones as shown.
Gwar [14]

Answer:

If the ray of light is deflected by 45 degrees by the first mirror its total deflection by mirror (I) is 90 deg. (incident = 45 and exit ray equals 45 deg)

The second mirror will cause a net deflection of 90 degrees and the total deflection will be 180 deg or in opposite  direction to the  incident ray.

3 0
2 years ago
"A toy airplane flies clockwise at a constant speed in a horizontal circle of radius 8.0 meters. The magnitude of the accelerati
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For the answer to the question above, so at the instant, the acceleration of the airplane is southward, the direction of the velocity is also southward. The direction should be the same because it is both a vector quantity and it does not make sense if the direction and acceleration have different direction.
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3 years ago
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Describe how can two or more velocities be combined
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Two or more velocities add by vector addition
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3 years ago
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