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miv72 [106K]
3 years ago
12

Which rules are violated in the following electronic configuration 1s2 2s3​

Chemistry
1 answer:
aalyn [17]3 years ago
5 0
There is no element in 2s3
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Which of the following statements is not true of the process of nuclear fission? (3 points) It is the process used in most nucle
Misha Larkins [42]
Answer: the statement that is not true is the second one: <span>It only occurs in very small atoms with low mass.

Explanation:

</span><span>The nuclear fission consists in the division or fragmentation of an atomic nuclei into smaller fragments releasing huge amounts of energy.

The biggest and heaviest atoms are unstable, meaning that they gain stability by splitting into smaller, lighter atoms.

So, the third given statement contradicts the previous fact.

That is why most of the heaviest elements have not been found naturally but have been created synthetically and have very short life times.
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6 0
4 years ago
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18 Reema observed that most of the fish in the pond of her village were gradually dying. She
juin [17]

Answer:

a. The fish are dying due to factory pollution making the water of the pond uninhabitable.

b. The pond can be neutralized by adding something basic to balance the pH levels of the pond, or by adding significant amounts of water to dillute the acidity of the pond.

3 0
3 years ago
. Use the following reaction to determine how much of each product would be released if 42 000 kg (42 tonnes) of methyl isocyana
fenix001 [56]

The amount of 1,3-dimethyl urea produced would be 32,458 grams or 32.458 kg while that of carbon dioxide would be 16,214 grams of 16.214 kg

<h3>Stoichiometric problem</h3>

From the equation of the reaction, the mole ratio of methyl isocyanate with the products is 2:1 respectively.

Mole of 42,000 kg of methyl isocyanate = 42000/57 = 736.84 moles

Equivalent mole of 1,3-dimethyl urea = 736.84/2 =368.42 moles

Equivaent mole of carbon dioxide = 736.84/2 =368.42moles

Mass of 368.42 moles 1,3-dimethyl urea = 368.42 x 88.1 = 32,458 grams or 32.458 kg

Mass of 368.42 moles of carbon dioxide = 368.42 x 44.01 = 16,214 grams of 16.214 kg

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

5 0
2 years ago
A 275-mL flask contains pure helium at a pressure of 752 torr. A second flask with a volume of 475 mL contains pure argon at a p
hichkok12 [17]

Answer:

  • Partial pressure He = 276 torr
  • Partial pressure Ar = 457 torr
  • Total pressure = 733 torr

Explanation:

Assuming temperature remains constant, we can use Boyle's law to solve this problem: P₁V₁=P₂V₂.

Once the two flasks are connected and the stopock opened, the total volume is:

  • 275 + 475 = 750 mL

Now we use Boyle's law <em>twice</em>, to <u>calculate the new pressure of </u><em><u>each</u></em><u> gas</u>:

  • He ⇒ 752 torr * 275 mL = P₂He * 750 mL

P₂He = 276 torr

  • Ar ⇒ 722 torr * 475 mL = P₂Ar * 750 mL

P₂Ar = 457 torr

Finally we <u>calculate the total pressure</u>, adding the partial pressures:

  • Total pressure = P₂He + P₂Ar = 733 torr
4 0
3 years ago
The area of a rectangle is 50 m2<br> If the height is 4 m, what is the<br> base?
Oliga [24]

Area = height × base

50 = 4 × base

Thus

base = 50/4

Base = 12.5 m

6 0
3 years ago
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