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FromTheMoon [43]
2 years ago
13

(pls help me)

Chemistry
2 answers:
kari74 [83]2 years ago
7 0
Claim 1 Sounds more convincing then claim 2
KATRIN_1 [288]2 years ago
5 0

Answer:

Claim 1

Explanation:

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X^2/2x^5=2<br><br>how do you solve this ?
Natasha2012 [34]

Answer:

x=\sqrt[3]{\frac{1}{4}}

Explanation:

\displaystyle\frac{x^2}{2x^5}=2\\\\x^2=4x^5\\\\1=4x^3\\\\x^3=\frac{1}{4}\\\\\\x=\sqrt[3]{\frac{1}{4}}

8 0
2 years ago
Scientists tracking the populations of certain freshwater fish have found an increase in the female to male ratio of several sma
vodomira [7]
I believe that the answer to the question provided above is that <span>they formed two very different hypotheses since it is what they saw according to what they knew. Also hypothesis is just an intelligent guess.</span>
Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
7 0
3 years ago
Read 2 more answers
Which ocean zone lies inside V-shaped ocean trenches? O A. Bathypelagic O B. Abyssopelagic Ο Ο Ο Ο O C. Mesopelagic O D. Hadalpe
alisha [4.7K]

Answer:

O D. Hadalpelagic is the answer.

5 0
3 years ago
The carbon atoms in saturated hydrocarbons ________. Group of answer choices contain a benzene ring contain at least one double
Aliun [14]

Answer:

Have only single bonds.

Explanation:

Hello,

In this case, we need to remember that saturation is a state at which a carbon chain contains no insaturations, that is neither double nor triple bonds such case are alkenes and alkynes, but saturations only which are characterized by the presence of single bonds between adjacent carbon atoms. Such is the case of ethane (CH₃-CH₃), propane (CH₃-CH₂-CH₃), butane (CH₃-CH₂-CH₂-CH₃) and so on.

Best regards.

4 0
3 years ago
True or False: In every gram of sucrose (table sugar) there is 0.513 g of oxygen
Ber [7]

Answer:

True

Explanation:

Step 1: Find molecular formula of sucrose

C₁₂H₂₂O₁₁

Step 2: Convert moles of oxygen present to grams

1 mol O = 16 g O

11 mol O = 176 g O

Step 3: Find molar mass of sucrose

C - 12.01 g/mol

H - 1.01 g/mol

O - 16.00 g/mol

12.01(12) + 22(1.01) + 11(16.00) = 342.34 g/mol C₁₂H₂₂O₁₁

Step 4: Set up dimensional analysis

1 gC_{12}H_{22}O_{11}(\frac{176 gO}{342.34gC_{12}H_{22}O_{11}} )

Step 5: Multiply/Divide and cancel out units

Grams of C₁₂H₂₂O₁₁ and grams of C₁₂H₂₂O₁₁ cancel out.

We are left with grams Oxygen

176/342.34 = 0.514109 grams Oxygen

4 0
3 years ago
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