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Levart [38]
2 years ago
13

What is the shape of the waterline?

Chemistry
1 answer:
Vikentia [17]2 years ago
5 0
The waterline is where the hull of a ship meets the surface of the water, it is also a special marking indicating the legal load limit of a ship, and, in naval architectural plans, it is any line drawn to delineate hull shape that is in a plane parallel to the surface of the water.
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1. Chemical equilibrium is established when the number of reactants equals the number of products.. . - True. - False. . 2. Acco
torisob [31]
<span>1)false a in chemical equilibrium concentration of reactant is equal to concentration of product
 2)as here they said heat is added in product side means its endothermic reaction and in endothermic reaction on increasing temp. equilibrium shift towards forward direction so its true
 3) B)as here mole are equal in reactant and product side that is 2 and if we increase pressure equilibrium shift in dat direction where no. of moles are less and here mole are equal so it will remain unaffected</span>
7 0
3 years ago
Read 2 more answers
What can you conclude about these two reactions based on the chemical equations? Reaction A: 6CO2(g) + 6H2O(l) + sunlight ? C6H1
OlgaM077 [116]

Given reactions:

(A)   6CO2(g) + 6H2O(l) + sunlight → C6H12O6(aq) + 6O2(g)

(B)  2H2(g) + O2(g) → 2H2O(g) + energy

Exothermic reactions are those which proceed with the release of heat/energy. In contrast, endothermic reactions proceed with the absorption of energy in the form of heat or light.

Since reaction A required sunlight, it is endothermic. Reaction B releases energy, hence exothermic

Ans: (B)

A is endothermic

B is exothermic


8 0
2 years ago
Find a mole of 0.0960 g of H2SO4
nignag [31]
Molar mass H₂SO₄ = 98.079 g/mol

1 mol -------- 98.079 g
? mole ------ 0.0960 g

moles = 0.0960 * 1 / 98.079

= 0.0960 / 98.079

= 9.788 x 10⁻⁴ moles

hope this helps!
3 0
3 years ago
If a young girl learned that it would be 0° C, or 32° F, the next
Ad libitum [116K]

Answer:

Cold

Explanation:

Because 0°C And below or 32°F Refers To Cold Weather

7 0
2 years ago
For each of the following cases, identify the order with respect to the reactant, A. Case (A ----&gt; product)
damaskus [11]

Answer:

The answers to the question are

1. 2nd and above order order

2. 2nd order

3. 1/2 order

4.  1st order

5. 0 order

Explanation:

We have \frac{N}{N_{0} } = e^{-\lambda t}

1. For nth order reaction half life  t_{\frac{1}{2} } ∝ \frac{1}{[A_{0} ]^{n-1} }

Therefore for a 0 order reaction increasing concentration of the reactant there will increase   t_{\frac{1}{2} }

First order reaction    is independent  [A₀].

Second order reaction  [A₀] decrease,    increase.

Similarly for a  third order reaction

1. 2nd order

2. 2nd order reaction

3. Order of reaction is 1/2.

4. 1st order reaction.

5. Zero order reaction.

5 0
3 years ago
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