Answer:
V₂ = 50.93 L
Explanation:
Initial volume, ![V_1=43.1\ L](https://tex.z-dn.net/?f=V_1%3D43.1%5C%20L)
Initial temperature, ![T_1=24^{\circ} C=24+273=297\ K](https://tex.z-dn.net/?f=T_1%3D24%5E%7B%5Ccirc%7D%20C%3D24%2B273%3D297%5C%20K)
Final temperature, ![T_2=78^{\circ} C=78+273=351\ K](https://tex.z-dn.net/?f=T_2%3D78%5E%7B%5Ccirc%7D%20C%3D78%2B273%3D351%5C%20K)
We need to find the final volume of the gas. The relation between the volume and the temperature is given by :
![\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{43.1\times 351}{297}\\\\V_2=50.93\ L](https://tex.z-dn.net/?f=%5Cdfrac%7BV_1%7D%7BT_1%7D%3D%5Cdfrac%7BV_2%7D%7BT_2%7D%5C%5C%5C%5CV_2%3D%5Cdfrac%7BV_1T_2%7D%7BT_1%7D%5C%5C%5C%5CV_2%3D%5Cdfrac%7B43.1%5Ctimes%20351%7D%7B297%7D%5C%5C%5C%5CV_2%3D50.93%5C%20L)
So, the final volume of the gas is 50.93 L.
Answer:
The coefficient before potassium (K) balances this chemical equation is 2.
Explanation:
_K +Cl₂ → 2KCl
K =1 ; Cl =2
K=1 × 2 = 2![](https://tex.z-dn.net/?f=)
Cl = 1 × 2 = 2
2 K +Cl₂ = 2 KCl
The metals are to the left of the line (except for hydrogen, which is a nonmetal), the nonmetals are to the right of the line, and the elements immediately adjacent to the line are the metalloids.
hope it helps...!!!
Answer: The empirical formula for C6H12O6 is CH2O. Every carbohydrate, be it simple or complex, has an empirical formula CH2O
Explanation: