Atoms like in chemistry class?
B burning a piece of wood
Ash is a chemical substance not apparent before the chemical change,the fire burning the wood
Answer: The final temperature is 
Explanation:
As we know that,
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
.................(1)
where,
q = heat absorbed or released
= mass of lead = 50 g
= mass of water = 75 g
= final temperature = ?
= temperature of lead = 
= temperature of water = 
= specific heat of lead = 
= specific heat of water= 
Now put all the given values in equation (1), we get
![50\times 0.11\times (T_{final}-373)=-[75\times 1.0\times (T_{final}-273)]](https://tex.z-dn.net/?f=50%5Ctimes%200.11%5Ctimes%20%28T_%7Bfinal%7D-373%29%3D-%5B75%5Ctimes%201.0%5Ctimes%20%28T_%7Bfinal%7D-273%29%5D)
Therefore, the final temperature of the mixture will be 279.8 K.
Answer:
Specific heat of metal = 0.26 j/g.°C
Explanation:
Given data:
Mass of sample = 80.0 g
Initial temperature = 55.5 °C
Final temperature = 81.75 °C
Amount of heat absorbed = 540 j
Specific heat of metal = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 81.75 °C - 55.5 °C
ΔT = 26.25 °C
540 j = 80 g × c × 26.25 °C
540 j = 2100 g.°C× c
540 j / 2100 g.°C = c
c = 0.26 j/g.°C
