Answer:
80.92, Krypton
Explanation:
<u>What is effusion?</u>
• It is a process where gas escapes through a pinhole (a very small hole) into a region of low pressure or vacuum
<u>Graham's law of effusion of </u><u>gas</u>
• states that at a given constant temperature and pressure, the rate of effusion of gases is inversely proportional to the square root of their molar masses
![\boxed{ \frac{Rate_1}{Rate_2} = \sqrt{ \frac{M_2}{M_1} } }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5Cfrac%7BRate_1%7D%7BRate_2%7D%20%3D%20%20%5Csqrt%7B%20%5Cfrac%7BM_2%7D%7BM_1%7D%20%7D%20%7D)
<u>Calculations</u>
Nitrogen exist as N₂ at room temperature, thus its molar mass is 2(14)= 28.
Let the rate and molar mass of unknown gas be Rate₂ and M₂ respectively.
Since N₂ effuses 1.7 times as fast as the unknown gas,
Rate₁= 1.7(Rate₂)
![\frac{Rate_1}{Rate_2} = 1.7](https://tex.z-dn.net/?f=%5Cfrac%7BRate_1%7D%7BRate_2%7D%20%3D%201.7)
![1. 7 = \sqrt{ \frac{M_2}{28} }](https://tex.z-dn.net/?f=1.%207%20%3D%20%20%5Csqrt%7B%20%5Cfrac%7BM_2%7D%7B28%7D%20%7D%20)
Square both sides:
![2.89 = \frac{M_2}{28}](https://tex.z-dn.net/?f=2.89%20%20%3D%20%5Cfrac%7BM_2%7D%7B28%7D%20)
Multiply both sides by 28:
2.89(28)= M₂
M₂= 80.92
<u>Identity of </u><u>gas</u>
The molar mass of 80.92 lies between Bromine and Krypton. However since Bromine exist as Br₂, the value of it's molar mass would be 159.8 instead. Hence, Bromine is eliminated.
If the gas is a diatomic element, the atomic weight is 80.92 ÷2= 40.46. Thus, we are now considering if Argon could be its identity. However, Argon is a noble gas and will not exist as a diatomic element. Argon is therefore eliminated too.
Thus based on the above reasoning, its probable identity is Krypton.