1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mario62 [17]
3 years ago
10

Carbon dioxide enters an adiabatic compressor at 100 kPa and 300K at a rate of 0.5 kg/s and leaves at 600 kPa and 450K. Neglecti

ng kinetic energy changes, determine a) the volume flow rate of the carbon dioxide at the compressor inlet (Ans. around 0.3 m3/s) and b) the power input to the compressor (Ans. around 70 kW).

Physics
2 answers:
Leona [35]3 years ago
8 0

Explanation:

Below is an attachment containing the solution.

Nastasia [14]3 years ago
5 0

Answer:

The answers to the question are

a) The volume flow rate of the carbon dioxide at the compressor inlet is 0.2834 m³/s ≈ 0.3 m³/s

b) The power input to the compressor is 73.35 kW ≈ 70 kW

Explanation:

We note the following

Mass flow rate = 0.5 kg/s

Inlet pressure = 100 pKa

Outlet pressure = 600 kPa

Inlet temperature = 300 K

Outlet temperature  =  450 K

Molar mass of CO₂ = 44.01 g/mol

R Universal Gas Constant = 8.314 4621. J K−1 mol−1

a) Number of moles = \frac{Mass}{Molar.Mass} = \frac{500g}{44.01g} = 11.361 moles

P·V= n·R·T ∴ V = \frac{n*R*T}{P} = \frac{11.361*8.3145*300}{ 100 } = 0.2834 m³

Therefore the volume flow rate = 0.2834 m³/s ≈ 0.3 m³/s

b) Cp at 300 K = 0.846 kJ/(kg K)

Cp at 600 K = 0.978 kJ/(kg K)

Cv = 0.657

K = 1.289

While the power input to the compressor can be calculated by

m'×Cp×(T₂-T₁)

Where m' = mass flow rate = 0.5 kg/s

Therefore power = 0.5 kg/s×0.978 kJ/(kg K)×(450 K - 300 K)

= 73.35 kJ/s = 73.35 kW ≈ 70 kW

You might be interested in
Dolphins communicate using compression waves (longitudinal waves). Some of the sounds dolphins make are outside the range of hum
lana66690 [7]

Answer: send the message underwater because a more dense medium would make the sound travel faster.

Explanation:

Dolphins communicate using compression waves - longitudinal waves. Longitudinal waves requires a medium to travel. A longitudinal wave transfers energy by the vibration of medium particles in the direction of the wave motion. Compression are the regions where density of the medium is higher and rarefaction is a low density region.

A longitudinal wave travels faster in a denser medium. It has maximum speed in solid and minimum in gas. Thus, to transfer message quickly to dolphin B., dolphin A should send the message underwater and not in air. This is because water has higher density than air. Molecules collide more quickly in water than in air and it takes less time for signal to travel.

3 0
3 years ago
30cm³ of brine of relative density 1.15 and 42cm³ of water are mixed. What is the density of the final solution​
Aleks04 [339]

Answer:

I think it's the most important part in this

7 0
3 years ago
What are some ways that humans depend on the ocean?
yulyashka [42]

Answer:

A lot of the earth oxygen comes from the ocean around 50%-80%

Explanation:

5 0
2 years ago
Read 2 more answers
A 2kg block of which material would require 450 joules of thermal energy to increase its temperature by 1 degree Celsius?
12345 [234]

The block is made of A) Tin, as its specific heat capacity is 0.225 J/(g^{\circ}C)

Explanation:

When an amount of energy Q is supplied to a sample of material of mass m, the temperature of the material increases by \Delta T, according to the following equation :

Q=mC_s \Delta T

where  C_s is the specific heat capacity of the material.

In this problem, we have:

m = 2 kg = 2000 g is the mass of the unknown material

Q = 450 J is the amount of energy supplied to the block

\Delta T = 1^{\circ}C is the change in temperature of the material

Solving the equation for C_s, we can find the specific heat capacity of the unknown sample:

C_s = \frac{Q}{m \Delta T}=\frac{450}{(2000)(1)}=0.225 J/(g^{\circ}C)

And by comparing with tabular values, we can find that this value is approximately the specific heat capacity of tin.

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

7 0
3 years ago
On a highway curve with a radius of 46 meters, the maximum force of static friction that can act on a 1,200 kg car going around
Mekhanik [1.2K]

Answer:

v\approx 16.956\,\frac{m}{s}

Explanation:

The motion of the vehicule on a highway curve can be modelled by the following equation of equilibrium:

\Sigma F = f = m\cdot \frac{v^{2}}{R}

The maximum speed is:

v = \sqrt{\frac{f\cdot R}{m} }

v = \sqrt{\frac{(7500\,N)\cdot (46\,m)}{1200\,kg} }

v\approx 16.956\,\frac{m}{s}

7 0
3 years ago
Other questions:
  • As the plates continues to grind against each other,what geologic events could take place
    13·2 answers
  • X-rays can be dangerous. Please select the best answer from the choices provided T F
    10·2 answers
  • A heat engine operating between energy reservoirs at 20?c and 600?c has 30% of the maximum possible efficiency.
    7·1 answer
  • Which of the following best defines boiling point?
    9·1 answer
  • An atom has 25 protons 30 neutrons and 25 electrons what is the charge of the atom nucleus
    7·1 answer
  • A localized impediment to electron flow in a circuit is a:
    6·2 answers
  • A helicopter carries a 1000-kg-car suspended from a rope below it. The helicopter flies horizontally at a constant speed of 25 m
    13·1 answer
  • Describe Charle’s Law and Boyle’s Law.
    5·1 answer
  • Place the following types of electromagnetic radiation in order from LOWEST energy
    14·1 answer
  • a lunar probe is moving 1670 m/s at a 73.0 angle. it needs to land on the moon 3.71 x 10^8 m away in a 46.0 direction in 8.64 x
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!