m = mass of the cat being lifted = 5 kg
h = height to which the cat is raised into air = 2 m
g = acceleration due to gravity of earth = 9.8 m/s²
U = gravitational potential energy gained by the cat
Gravitational potential energy gained by the cat is given as
U = m g h
inserting the values in the above equation
U = (5 kg) (9.8 m/s²) (2 m)
U = (5 x 9.8 x 2) (kg m²/s²)
U = 98 J
When you exert a force on the coin, it will accelerate. If you push the coin and it moves at a constant velocity, the friction force must be equal to the force that you are exerting. This is an example of a balanced force. When the net force is greater than 0 N, the is an unbalanced force.
Answer:
Distance: 75 km
Displacement: 45 km
Explanation:
- Distance is a scalar quantity that refers to the total space covered by an object. It is calculated as the sum of the distances covered in each motion, regardless of their direction. therefore in this case:
distance = 60 km + 15 km = 75 km
- Displacement is a vector quantity whose magnitude is equal to the difference between the final point and the starting point of the motion, so it also takes into account the direction of each motion. In this case, the truck moves 60 km east, and then 15 km west: if we call '0' the starting point, the final point will be then

And so the displacement is
