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Nezavi [6.7K]
3 years ago
10

Explain how to find the angle between two nonzero vectors. Choose the correct answer below. A. The angle between two nonzero vec

tors can be found by first dividing the dot product of the two vectors by the product of the twoâ vectors' magnitudes. Then taking the inverse cosine of the result. B. The angle between two nonzero vectors can be found by first dividing the product of the twoâ vectors' magnitudes by the dot product of the two vectors. Then taking the inverse cosine of the result. C. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the twoâ vectors' magnitudes. Then taking the inverse sine of the result. D. The angle between two nonzero vectors can be found by first dividing the product of the twoâ vectors' magnitudes by the dot product of the two vectors. Then taking the inverse sine of the result.
Physics
1 answer:
kozerog [31]3 years ago
3 0

Answer:

θ = Cos⁻¹[A.B/|A||B|]

A. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the two vectors' magnitudes. Then taking the inverse cosine of the result

Explanation:

We can use the formula of the dot product, in order to find the angle between two non-zero vectors. The formula of dot product between two non-zero vectors is written a follows:

A.B = |A||B| Cosθ

where,

A = 1st Non-Zero Vector

B = 2nd Non-Zero Vector

|A| = Magnitude of Vector A

|B| = Magnitude of Vector B

θ = Angle between vector A and B

Therefore,

Cos θ = A.B/|A||B|

<u>θ = Cos⁻¹[A.B/|A||B|]</u>

Hence, the correct answer will be:

<u>A. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the two vectors' magnitudes. Then taking the inverse cosine of the result</u>

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We substitute

      k q q / x₃² = k 4q q / (2-x₃)²

      q² (2 - x₃)² = 4 q² x₃²

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Now  since capacitance is  constant  at  \tau  =  3

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4 0
3 years ago
a. When the electric field between the plates is 75% of the dielectric strength and energy density of the stored energy is 2800
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Substitutes C in the first formula into the energy formula.

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Let us remember that electric field strength E is the ratio of potential V to the distance d. Where V = Ed

Substitute V = Ed into the energy W.

W = 1/2 × ε A/d ×( Ed )^2

W = 1/2 × ε A/d × E^2 × d^2

d will cancel one of the ds

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2800 = 1/2 × ε E^2

2800 = 0.5 × ε × (18.9×10^6)^2

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ε = 1.57 × 10^-11

Dielectric constant k = relative permittivity

Relative permittivity is the ratio of the permittivity of the material to the permittivity of the vacuum in a free space. That is

k = 1.57×10^-11/8.84×10^-12

k = 1.776

k = 1.8 approximately

Therefore, the value of the dielectric constant k is 1.8

3 0
3 years ago
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