Answer:
M = 1.98g
Explanation:
Please see the attachment below.
For the mass to balance the force of repulsion, the gravitational force on the mass (its weight) must equal the magnetic force of repulsion between the straight rods.
So
Mg = μo ×I ×I' × L/2πr
M = μo ×I ×I' × L/2πrg
Given
I = I' = 18A
L = 60cm = 0.6m
r = 2mm = 2×10-³m
μo = 4π×10-⁷Tm/A
g = 9.8m/s²
M = (4π×10-⁷ × 18² × 0.6)/(2π×2×10-³ ×9.8) = 1.98 ×10-³ kg.
Answer:
Accelerate up more compressed spring
Accelerate down spring less compressed
Explanation:
For this problem we must analyze the forces that act on the scale on the one hand the weight of the man directed downwards and I have the other the elastic force of the spring directed upwards. Now let's write Newton's second law for these forces in various configurations,
When the elevator is quiet or moving at constant speed
Fe - W = 0 ⇒ Fe = W -k x = mg x = mg /k
Fe = mg
We use this value to compare
Now let's analyze when the elevator accelerates upwards
Fe -W = m a
Fe = ma + W
Fe = m (a + g)
So we can see that Fe increases, so the compression of springs is higher
Now let's analyze when the elevator acceleration is down
Fe -W = m (-a)
Fe = w - m a
Fe = m (g -a)
In this case Fe is smaller, so the compression of the spring is less
Given data
mass (m) =8 Kg ,
speed (v) =10 m/s ,
time (t) = 5 s
determine magnitude of force (Fnet) = ?
we knoe that
Fnet = m.a
= 8 × (v/t) since a = v/t
= 8 × (10/5)
= 16 N
<em>Magnitude of net force is 16 N</em>
Answer:
a the answer is letter A the first one
Answer:
22044.3 N
Explanation:
We are given that
Dimension of office window=
Area of office window=
Outside air pressure=P1=0.972 atm
Inside pressure,P2=1.0 atm
Pressure=P2-P1=1-0.972=0.028 atm=0.028\times 101325 Pa=2837.1 Pa
1 atm=101325 Pa
Force,F=PA
Using the formula
Hence, the net force pushes out on the window=22044.3 N
