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Eduardwww [97]
4 years ago
14

For a home sound system, two small speakers are located so that one is 52 cm closer to the listener than the other. What is the

very first frequency of audible sound for these speakers to produce destructive interference at the listener?The speed of sound is 344 m/sec. (1 point)
A. 166 Hz
B. 331 Hz
C. 662 H2
D. 1323 H
Physics
1 answer:
galina1969 [7]4 years ago
7 0

Answer:

The first frequency of audible sound in the speed sound is

f = 662 Hz

Explanation:

vs = 344 m/s

x =  52 cm * 1 / 100m = 0.52m

The wave length is the distance between the peak and peak so

d = 2x

d = 2*0.52 m

d = 1.04 m

So the frequency in the speed velocity is

f = 1 / T

f = vs / x = 344 m/s / 0.52m

f ≅ 662 Hz

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Two straight rods 60 cm long and 2.0 mm apart in a current balance carry currents of 18 A each in opposite directions. What mass
WARRIOR [948]

Answer:

M = 1.98g

Explanation:

Please see the attachment below.

For the mass to balance the force of repulsion, the gravitational force on the mass (its weight) must equal the magnetic force of repulsion between the straight rods.

So

Mg = μo ×I ×I' × L/2πr

M = μo ×I ×I' × L/2πrg

Given

I = I' = 18A

L = 60cm = 0.6m

r = 2mm = 2×10-³m

μo = 4π×10-⁷Tm/A

g = 9.8m/s²

M = (4π×10-⁷ × 18² × 0.6)/(2π×2×10-³ ×9.8) = 1.98 ×10-³ kg.

7 0
4 years ago
Would the springs inside a bathroom scale be more compressed or less compressed if you weighed yourself in an elevator that acce
Delvig [45]

Answer:

Accelerate up more compressed spring

Accelerate down spring less compressed

Explanation:

For this problem we must analyze the forces that act on the scale on the one hand the weight of the man directed downwards and I have the other the elastic force of the spring directed upwards. Now let's write Newton's second law for these forces in various configurations,

When the elevator is quiet or moving at constant speed

       Fe - W = 0      ⇒    Fe = W         -k x = mg    x = mg /k

       Fe = mg

We use this value to compare

Now let's analyze when the elevator accelerates upwards

      Fe -W = m a

     Fe = ma + W

     Fe = m (a + g)

So we can see that Fe increases, so the compression of springs is higher

Now let's analyze when the elevator acceleration is down

    Fe -W = m (-a)

    Fe = w - m a

    Fe = m (g -a)

In this case Fe is smaller, so the compression of the spring is less

5 0
4 years ago
A net force acts on a mass of 8.00 kg causing it to move from rest to a speed of 10.0 m/s in a time of 5.00 s. The bet force mus
wolverine [178]

Given data

mass (m) =8 Kg ,

speed (v) =10 m/s ,

time (t) = 5 s

determine magnitude of force (Fnet) = ?

                    we knoe that

                                        Fnet = m.a

                                                 = 8 × (v/t)       since a = v/t

                                                 = 8 × (10/5)

                                                 = 16 N

<em>Magnitude of net force is 16 N</em>


4 0
3 years ago
[30 POINTS] <br><br> can someone please answer 2-4 for me
Sonja [21]

Answer:

a the answer is letter A the first one

8 0
4 years ago
An office window has dimensions 3.7 m by 2.1 m. As a result of the passage of a storm, the outside air pressure drops to 0.972 a
Katyanochek1 [597]

Answer:

22044.3 N

Explanation:

We are given that

Dimension of office window=3.7m\times 2.1 m

Area of office window=l\times b=3.7\times 2.1=7.77 m^2

Outside air pressure=P1=0.972 atm

Inside pressure,P2=1.0 atm

Pressure=P2-P1=1-0.972=0.028 atm=0.028\times 101325 Pa=2837.1 Pa

1 atm=101325 Pa

Force,F=PA

Using the formula

F=7.77\times 2837.1=22044.3 N

Hence, the net force pushes out on the window=22044.3 N

8 0
4 years ago
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