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Allushta [10]
3 years ago
5

According to Le Chatlelier's Principle,

Chemistry
1 answer:
Len [333]3 years ago
4 0
The answer to this question is D
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Calculate the density of a sample of gold if the sample has a volume of 48.9cm3 and a mass of 944.75 g
LekaFEV [45]

Answer:

19.3g/cm^3

Explanation:

Hey,

the formula for density is Mass/Volume so in this question you basically put the given things in the formula

D = M/V

D= 944.75/48.9

D= 19.3g/cm^3

7 0
3 years ago
Read 2 more answers
What chemical bonds stabilize the different structures in primary, secondary, tertiary and quaternary structures?.
Blababa [14]

Peptide bonds, hydrogen bonds, disulfide linkages, van der Waals, and electrostatic forces of attraction are the chemical bonds that stabilize the different structures in primary, secondary, tertiary, and quaternary structures.

The advanced structure of proteins gives rise to two kinds of major molecular shapes which are fibrous as well as globular structures. The main forces which are involved in stabilizing the secondary along with the tertiary structures of proteins include hydrogen bonds, disulfide type linkages, van der Waals attraction, and electrostatic forces of attraction.

The primary structure is generally determined by adjoining peptide bonds where the link is adjoining amino acids in sequential order. Tertiary structure is determined by the existence of disulfide bonds in between hydrophobic interactions as well as cysteine residues whereas the quaternary type structure is determined by multiple subunits of a protein that undergo various interactions.

Hydrogen bonds exist in a protein molecule as its large number can form between adjacent regions of the polypeptide chain in folded form and stabilize its three-dimensional kind of shape.

Learn to know more about levels of protein structure on

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4 0
1 year ago
Can someone answer pls
USPshnik [31]
I think it would be 196
7 0
3 years ago
a sample of gas occupies 2.00 liters under standard conditions. what temperatures would be required for this sample of gas to oc
gogolik [260]

Answer: 1,638

Explanation:

3 0
3 years ago
How many molecules of CH4 are in 48.2 g of this compound? A) 2.00 x 1023 B) 5.00 x 10-24 C)1.81 x 1024 D) 4.00 E) 4.64 x 1026 10
Tasya [4]

<u>Answer:</u> The correct answer is Option C.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of methane = 48.2 g

Molar mass of methane = 16 g/mol

Putting values in above equation, we get:

\text{Moles of }CH_4=\frac{48.2g}{16g/mol}=3.0125mol

According to mole concept:

1 mole of compound contains 6.022\times 10^{23} number of molecules.

So, 3.0125 moles of methane will contain = 3.0125\times 6.022\times 10^{23}18.141\times 10^{23}=1.81\times 10^{24} number of molecules.

Hence, the correct answer is Option C.

8 0
3 years ago
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