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Lady_Fox [76]
3 years ago
7

State the importance of oxygen for germination process

Chemistry
1 answer:
tamaranim1 [39]3 years ago
3 0
Plants need oxygen to survive. 
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When body temperature rises during physical activity, which thermoregulatory response is stimulated?
navik [9.2K]

Answer: Heat dissipation mechanism

Explanation: Heat dissipation mechanism is a thermoregulatory response in humans whereby the hypothalamus of the brain initiates certain processes to reduce the high body temperature. Eg, sweating is initiated which helps cool down the body temperature, also superficial arteries are dilated, thereby leading to flushing and decreasing heatloss into the air. And metabolic heat production is also reduced.

8 0
3 years ago
99% of matter that makes up living organisms consists of how many elements?
DiKsa [7]

Answer:

h2o or air

Explanation:

6 0
4 years ago
In a chemical reaction 88g of CO2 was produced at r.t.p. <br> Calculate the volume of CO2 in dm??
Tems11 [23]

Explanation:

RFM = 44 \: g \\ 44g \: contain \: 1 \: mole \\ 88g \: will \: contain \: ( \frac{88}{44}  \times 1) \\  = 2 \: moles \\ at \: room \: temperature \\ 1 \: mole \: occupies \: 24 \:  {dm}^{3}  \\ 2 \: moles \: occupies \: (2 \times 24) \\  = 48 \:  {dm}^{3}

6 0
3 years ago
He orbital period of an object is 2 × 107 s and its total radius is 4 × 1010 m
gtnhenbr [62]

Answer:

The answer is 12,560  

Explanation:

The orbital period is the time a given cosmic question takes to finish one circle around another protest and applies in space science as a rule to planets or space rocks circling the Sun, moons circling planets, exoplanets circling different stars, or double stars. Mercury, for instance, has an orbital time of 88 days while it takes Jupiter around 11.86 years. The time of the Earth's circle is generally thought to be 365 days as timetables appear.

6 0
3 years ago
Read 2 more answers
Calculate the mass in micrograms of zinc oxalate the chemist has added to the flask. be sure your answer has the correct number
Vera_Pavlovna [14]
<span>A chemist adds 155.0ml of a 4.10 X 10^-5 mmol/L of a zinc oxalate (ZnC2O4)solution to a reaction flask. Calculate the mass in micrograms of zinc oxalate the chemist has added to the flask. 1mmol = 10^-3 mol Therefore 4.10*10^-5mmol = 4.10*10^-8mol molar mass ZnC2O4 = 65.39+(2*12.011)+(4*15.99) = 153.372g/mol You have 4.10*10^-8 mol/litre =153.372 * 4.10*10^-8 = 6.29*10^-6 grams / litre (* see below) But you have 155ml. Mass of ZnC2O4 = 155/1000*6.29*10^-6 g Mass is = 9.75*10^-7 grams 1µg = 10^-6 g You then have 9.75*10^-7/10^-6 = 0.975µg ZnC2O4 (*see below) at this point you could have said: 1µg = 10^-6 g therefore you have a solution of 6.29µg per litre, 155ml = 6.29*155/1000 = 0.975µg ZnC2O4</span>
3 0
3 years ago
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