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Usimov [2.4K]
3 years ago
8

10. If 200. L of ammonia (NH3) are produced in the reaction between nitrogen and hydrogen at STP, how many

Chemistry
1 answer:
erma4kov [3.2K]3 years ago
8 0

Answer:

100L of N2

Explanation:

First let us obtain the number of mole of NH3 that occupied 200L at stp. This can be achieved by doing the following:

1mole of NH3 occupied 22.4L at stp.

Therefore, Xmol mole of NH3 will occupy 200L i.e

Xmol of NH3 = 200/22.4 = 8.93moles.

Now let us generate a balanced equation for the reaction.

N2 + 3H2 —> 2NH3

From the equation above,

1mole of N2 produced 2moles of NH3.

Therefore, Xmol of N2 will produce 8.93moles of NH3 i.e

Xmol of N2 = 8.93/2 = 4.47moles

Now let us convert 4.47moles to N2 to Litres. This is illustrated below:

1mole of N2 occupied 22.4L at stp

Therefore, 4.47moles of N2 will occupy = 4.47 x 22.4 = 100L

Therefore, 100L of N2 is used in the reaction

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The half-life of radium-226 is 1590 years. if a sample contains 100 mg, how many mg will remain after 1000 years?
AlladinOne [14]

Answer:

64.52 mg.

Explanation:

The following data were obtained from the question:

Half life (t½) = 1590 years

Initial amount (N₀) = 100 mg

Time (t) = 1000 years.

Final amount (N) =.?

Next, we shall determine the rate constant (K).

This is illustrated below:

Half life (t½) = 1590 years

Rate/decay constant (K) =?

K = 0.693 / t½

K = 0.693/1590

K = 4.36×10¯⁴ / year.

Finally, we shall determine the amount that will remain after 1000 years as follow:

Half life (t½) = 1590 years

Initial amount (N₀) = 100 mg

Time (t) = 1000 years.

Rate constant = 4.36×10¯⁴ / year.

Final amount (N) =.?

Log (N₀/N) = kt/2.3

Log (100/N) = 4.36×10¯⁴ × 1000/2.3

Log (100/N) = 0.436/2.3

Log (100/N) = 0.1896

Take the antilog

100/N = antilog (0.1896)

100/N = 1.55

Cross multiply

N x 1.55 = 100

Divide both side by 1.55

N = 100/1.55

N = 64.52 mg

Therefore, the amount that remained after 1000 years is 64.52 mg

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3 years ago
A gas at 750 mmhg and with a volume of 2. 00 l is allowed to change its volume at constant temperature until the pressure is 600
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Answer:

The new volume of a gas at 750 mmhg and with a volume of 2. 00 l when allowed to change its volume at constant temperature until the pressure is 600 mmhg is 2.5 Liters.

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Boyle's law states that the pressure of a given amount of gas is inversely proportional to it's volume at constant temperature. It is written as;

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P1 = Initial pressure of the gas = 750 mmHg

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V2 = P1 V1 ÷ P2

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V2 = 1500 ÷ 600

V2 = 2.5 Liters.

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