Answer:
100L of N2
Explanation:
First let us obtain the number of mole of NH3 that occupied 200L at stp. This can be achieved by doing the following:
1mole of NH3 occupied 22.4L at stp.
Therefore, Xmol mole of NH3 will occupy 200L i.e
Xmol of NH3 = 200/22.4 = 8.93moles.
Now let us generate a balanced equation for the reaction.
N2 + 3H2 —> 2NH3
From the equation above,
1mole of N2 produced 2moles of NH3.
Therefore, Xmol of N2 will produce 8.93moles of NH3 i.e
Xmol of N2 = 8.93/2 = 4.47moles
Now let us convert 4.47moles to N2 to Litres. This is illustrated below:
1mole of N2 occupied 22.4L at stp
Therefore, 4.47moles of N2 will occupy = 4.47 x 22.4 = 100L
Therefore, 100L of N2 is used in the reaction
