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Usimov [2.4K]
2 years ago
8

10. If 200. L of ammonia (NH3) are produced in the reaction between nitrogen and hydrogen at STP, how many

Chemistry
1 answer:
erma4kov [3.2K]2 years ago
8 0

Answer:

100L of N2

Explanation:

First let us obtain the number of mole of NH3 that occupied 200L at stp. This can be achieved by doing the following:

1mole of NH3 occupied 22.4L at stp.

Therefore, Xmol mole of NH3 will occupy 200L i.e

Xmol of NH3 = 200/22.4 = 8.93moles.

Now let us generate a balanced equation for the reaction.

N2 + 3H2 —> 2NH3

From the equation above,

1mole of N2 produced 2moles of NH3.

Therefore, Xmol of N2 will produce 8.93moles of NH3 i.e

Xmol of N2 = 8.93/2 = 4.47moles

Now let us convert 4.47moles to N2 to Litres. This is illustrated below:

1mole of N2 occupied 22.4L at stp

Therefore, 4.47moles of N2 will occupy = 4.47 x 22.4 = 100L

Therefore, 100L of N2 is used in the reaction

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Magnetism is believed to be caused by the alignment of small, numerous sub-units called
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Question 2: you have two systems: 1) solid gold and water 2) solid sodium and waterWhich one can spontaneously release energy an
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A chemical equation is shown below. KNO3 → KNO2 + O2 What are the coefficients that should be added to balance this equation? Us
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Potassium nitrate is decomposed on potassium nitrite and oxygen.

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There are two potassium atoms, two nitrogen atoms and six oxygen atoms on both side of balanced chemical reaction.  

Decomposition is reaction where one substance (in this example potassium nitrate) is broken down into two or more simpler substances (potassium nitrite and oxygen).  

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Metal higher in the reactivity series will displace another and it will be oxidized.

Magnesium is higher it this series than aluminium and aluminium is higher than copper.

22) The answer is: half life is 22 years.

Half-life is the time required for a quantity (in this example mass of the element) to reduce to half its initial value and is independent of initial concentration.

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λ  = 0.693 ÷ 22 y.

λ = 0.0315 1/y.

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ln(4.8125/308) = -0.0315 1/y · t₁.

t₁ = 132.02 y.

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Here is a site my buddie has to help you. Well co-owner..
https://www.quora.com/Why-is-fresly-prepared-FeSO4-required-for-the-ring-test
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