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3 years ago

10. If 200. L of ammonia (NH3) are produced in the reaction between nitrogen and hydrogen at STP, how many

Chemistry

1 answer:

erma4kov [3.2K]3 years ago

8 0

Answer:

100L of N2

Explanation:

First let us obtain the number of mole of NH3 that occupied 200L at stp. This can be achieved by doing the following:

1mole of NH3 occupied 22.4L at stp.

Therefore, Xmol mole of NH3 will occupy 200L i.e

Xmol of NH3 = 200/22.4 = 8.93moles.

Now let us generate a balanced equation for the reaction.

N2 + 3H2 —> 2NH3

From the equation above,

1mole of N2 produced 2moles of NH3.

Therefore, Xmol of N2 will produce 8.93moles of NH3 i.e

Xmol of N2 = 8.93/2 = 4.47moles

Now let us convert 4.47moles to N2 to Litres. This is illustrated below:

1mole of N2 occupied 22.4L at stp

Therefore, 4.47moles of N2 will occupy = 4.47 x 22.4 = 100L

Therefore, 100L of N2 is used in the reaction

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Answer:

The answer to your question is C₂HO₃

Explanation:

Data

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Carbon = 19.36%

Oxygen = 77.39%

Process

1.- Write the percent as grams

Hydrogen = 3.25 g

Carbon = 19.36 g

Oxygen = 77.39 g

2.- Convert the grams to moles

1 g of H ----------------- 1 mol

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x = (3.25 x 1) / 1

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x = (77.39 x 1)/16

x = 4.83

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Hydrogen = 1.61/1.61 = 1

Oxygen = 4.83/1.61 = 3

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C₂HO₃

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Explanation:

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__ KClO₃ → __ KCl + __ O₂

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Right Side:
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