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Agata [3.3K]
3 years ago
15

What product of the krebs cycle is considered a waste product of the reaction?

Chemistry
1 answer:
Rufina [12.5K]3 years ago
5 0
The answer is carbon dioxide 
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1. Igneous roc
2. Weathering & erosion
3. Sediments
4. Sedimentary rock
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6. Heat & pressure

Hope this is helpful
8 0
2 years ago
You want to determine the effect of a certain fertilizer on the growth of orchids grown in a greenhouse.
Aleks [24]
Hypothesis - I predict that the orchids will grow best with a medium concentration of fertilizer
3 0
2 years ago
An unknown liquid has a mass of 22.1 g
Yuki888 [10]
M = 22.1 g
V = 52.3 mL
D = ?

D = m/V
= 22.1/52.3
= 22.1*10/52.3*10
= 221/523
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6 0
3 years ago
The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calculate the volume of CO2 genera
nevsk [136]

Answer:

The volume of carbon dioxide gas generated 468 mL.

Explanation:

The percent by mass of bicarbonate in a certain Alka-Seltzer = 32.5%

Mass of tablet = 3.45 g

Mass of bicarbonate =3.45 g\times \frac{32.5}{100}=1.121 mol

Moles of bicarbonate ion = \frac{1.121 g/mol}{61 g/mol}=0.01840 mol

HCO_3^{-}(aq)+HCl(aq)\rightarrow H_2O(l)+CO_2(g)+Cl^-(aq)

According to reaction, 1 mole of bicarbonate ion gives with 1 mole of carbon dioxide gas , then 0.01840 mole of bicarbonate ion will give:

\frac{1}{1}\times 0.01840 mol=0.01840 mol of carbon dioxide gas

Moles of carbon dioxide gas  n = 0.01840 mol

Pressure of the carbon dioxide gas = P = 1.00 atm

Temperature of the carbon dioxide gas = T = 37°C = 37+273 K=310 K

Volume of the carbon dioxide gas = V

PV=nRT (ideal gas equation)

V=\frac{nRT}{P}=\frac{0.01840 mol\times 0.0821 atm L/mol K\times 310 K}{1.00 atm}=0.468 L

1 L = 1000 mL

0.468 L =0.468 × 1000 mL = 468 mL

The volume of carbon dioxide gas generated 468 mL.

5 0
3 years ago
When you slide a box across the floor what force must your push be stronger than?
weeeeeb [17]
If I remember correctly, the answer is <span>Friction force.</span>
6 0
3 years ago
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